So, what we can do instead of talking about the ionization energy, z because that's one of our known quantities, so that we can find z effective.
我们做的事可以代替讨论电离能,因为那是我们知道的量子数之一,那是我们可以解出有效的,如果我们重新排列这个方程。
And if we experimentally know z what the ionization energy is, we actually have a way to find out what the z effective will be equal to.
我们实际上就有了一个办法,去找出有效的,等于多少,我们可以使用这里的方程。
If we have a higher z effective, it's pulled in tighter, we have to put in more energy in order to eject an electron, so it turns out that that's why case 2 is actually the lowest energy that we need to put in.
而如果有效核电量更高,原子核的束缚也就更紧,我们不得不输入更多的能量来打出一个电子,这就是第二种情况,所需要输入的,能量更少的原因。
The z effective is lower, so we have to put less energy in to get an ion out.
它的有效核电量更低,所以我们只需要更少的能量就能打出一个离子。
So we should be able to calculate a z effective for any atom that we want to talk about, as long as we know what that ionization energy is.
我们应该可以计算出任何一个,我们想要谈论的原子的有效电荷量,只要我们知道电离能是多少。
So it looks like not too many more than half of you got this correct, so make sure you can look at your periodic table and figure out how to think about ionization energy in terms of z effective, not just in terms of memorizing what that trend is.
看起来只有一半多一点的人,做对了,所以请大家务必做到能够通过观察周期表,并在考虑电离能时,从有效核电量的观点出发,而不是仅仅依靠记住这个规律。
So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.
我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来,我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。
So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.
我们可以发现有效的z等于n的平凡,乘以电离能除以里德堡常数,这些所有再开方,所以等于n乘以,除以RH整体的平方根。
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