So I'm just going to re-draw my skeleton.
那么我要先把骨架重新写在这。
Well, I'm going to get back, let's just draw a bigger square than usual that's roughly four times the size.
嗯,返回的是,我画一个更大的方形,大致上是4倍的大小。
So what I'm going to do is I'm going to go back to my picture and draw these functions.
下面我们一起来,作出这些函数的图像
2 7 And I'm not going to draw the rest of the tree for you here, because I drew it last time, and you don't need to see the whole tree.
从这儿我们得到了,我在这里不会剩下的树都画出来,因为我上次画过了。
So any time I draw these molecular orbitals, I do my best, and I'm not always perfect, yet trying to make this energy different exactly the same for the anti-bonding orbital being raised, versus the bonding orbital being lowered.
所以我在画这些分子轨道的时候,虽然不是很完美,但我总是尽量,让反键轨道引起的,能量升高和成键轨道。
Now,in posing this question,I'm obviously presupposing that we can draw a distinction between the question,Do I survive?
提出这个问题的时候我显然已经假设,我们能够分清,我是否生存?
But there's another way to do this and I'm going to give you now the simplest example of the other way, which is to draw free-body diagrams.
不过还有另外一种方法,现在我来给你们演示,另外一种方法最简单的例子,也就是隔离法的受力分析
I'm going to draw an example.
我要举一个例子
And if I draw a diagram on a T-V diagram of T-V V1 I'm starting with some V1 here.
画出过程的,图,what,I’m,doing,here,初态是。
So, let's see this eraser actually never works very well so I'm just going to draw below it.
这个清除器不能很好地运行,我将在下面画出它。
When I draw something without an arrow, I'm talking about the magnitude.
如果我写下的字母没有箭头,那就说明我在讨论模长
I have no idea what's here at the moment so I'm just going to draw a question mark because that memory might have been used previously for some other purpose, but we know it's currently available to us so we have four bytes of memory.
我不知道在此刻这里是什么,所以我画一个问号,因为那块内存可能在之前,为其它的目的而使用过,但是我们知道它可以为我们所使用,这样我们就有4个字节的内存。
What I'm going to do is I want to draw the two functions we just found and see what they look like.
下面我们绘制两个函数图像,看看图像是什么样的
I'm going to draw a little chart here.
我将会在这里画几个表。
I'm not going to draw it, but it's something like this.
我就不去画了,道理是一样的
And I'm not quite sure how to draw that line.
而我并不确定界限在哪里。
What I want to do is I want to draw a picture here, in which on the horizontal axis, I'm going to put the probability of the other guy choosing Right.
我要在这里画一张图,坐标系的横轴,表示对手选右的概率
What I'm gonna do is draw a larger table, the same basic structure: I'm choosing Alpha and Beta on the rows, my pair is choosing Alpha and Beta on the columns, but now I'm going to put both grades in.
我要画个结构相同的大表格,用列来表示我选α还是β,用行来表示我对手选α还是β,但我要把两人成绩写在一个单元格里
So for each possible choice of S2, I'm going to draw Player I's best response and we'll do it in red.
对于任意定义域内的S2,我用红色来表示参与人I的最佳对策
Well, int is almost always 32 bits at least so far as we've seen so, in fact, any time I draw a pointer hence force I'm just going to draw a square as well because they are, in fact, the same size usually in memory.
嗯,int几乎总是32位的,至少我们至今所看到的是这样的,每次我用一个正方形表示一个指针,因为实际上他们,在内存中的大小是一样的。
I'll draw something from the distribution, so this is interesting, distribution I'm now calling self dot distribution, and remember this will be different for each stock.
我会从分布中读取一个值,这就是有趣的部分,我现在会调用self。,请记住每只股票都是不一样的。
So, let's just arbitrarily put it between these two in this case here, but actually there's no reason we couldn't also put it between oxygen b and c, so I'm going to draw another structure where we have it here.
那么,让我们任意地将它们放在这两个之间,但实际上我们没有理由,不能把它们放在氧原子,B,与,C,之间,因此我将把另外一个结构画在这里。
So we can draw that for 1 s a, we can also draw it for 1 s b, and what I'm saying for the molecular wave function is that we have the interference between the two, and we have a constructive interference, so we end up adding these two wave functions together.
所以我们可以对1sa画出它来,我们也可以对1sb画出它来,对于分子波函数我要说的是,它们两者之间会干涉,这里我们有相长干涉,所以我们得到的是波两个波函数加起来。
Excuse me. So what I'm going to do is, let's draw a picture that has S1 on the horizontal axis and S2 on the vertical axis.
好了,我们接下来来绘制图像,S1是横轴,S2是纵轴
I'm going to delete that arrow and actually draw s2 as pointing to this chunk of memory because whereas before this sequence of chars might have lived at address 71 or whatever, well, this one might live at 91.
我不会把那个箭头删除,实际上我画了s2作为,这块内存的指针,因为,这个字符序列存储在地址71或其它的地方,这个可能存储在91的地方。
If this is A, I'm going to draw a vector here.
如果这是矢量 A,我在这儿画个矢量
Okay, so I'm going to draw for the case, I'm going to draw the best response of Player I and I'm going to draw the best response for Player II in a minute, for the case B equals 1/4.
好的,我们要画这个案例的图像,我要在图中画出参与人I的最佳对策,一会还要画出参与人II的最佳对策,在这里B等于1/4
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