So any time I draw these molecular orbitals, I do my best, and I'm not always perfect, yet trying to make this energy different exactly the same for the anti-bonding orbital being raised, versus the bonding orbital being lowered.

所以我在画这些分子轨道的时候，虽然不是很完美，但我总是尽量,让反键轨道引起的，能量升高和成键轨道。

麻省理工公开课 - 化学原理课程节选

So for each possible choice of S2, I'm going to draw Player I's best response and we'll do it in red.

对于任意定义域内的S2,我用红色来表示参与人I的最佳对策

耶鲁公开课 - 博弈论课程节选

For each q2 that you give me or that Player 2 chooses, I want to find out and draw what is Player 1's best response.

对与参与人2的每个策略q2,我想知道参与人1的最佳对策是什么

耶鲁公开课 - 博弈论课程节选

Okay, so I'm going to draw for the case, I'm going to draw the best response of Player I and I'm going to draw the best response for Player II in a minute, for the case B equals 1/4.

好的,我们要画这个案例的图像,我要在图中画出参与人I的最佳对策,一会还要画出参与人II的最佳对策,在这里B等于1/4

耶鲁公开课 - 博弈论课程节选

So the expression I wanna draw first of all is the best response of Player I as a function of S2 and we agreed that that was given by 1 plus 1/4 now, 1 plus 1/4 S2.

首先我们想要绘制的表达式是,参与人I的最佳对策是S2的函数,我们都知道它等于1+S2/4

耶鲁公开课 - 博弈论课程节选

Now we can do the same for Player II, we can draw Player II's best response as it depends on the choices of Player I, but rather than go through any math, I already know what that line's going to look like.

同理也可以画出参与人II的图像,参与人II的最佳对策,取决于参与人I的策略,不用任何数学的方法,我就知道图像是什么样的了

耶鲁公开课 - 博弈论课程节选