• Y-Y -Yes, sir, I do.

    VOA: standard.other

  • These laws of nature, as he describes them, do not issue categorical commands so much as Y sort of hypothetical rules. If you want X, do Y; if you want peace, here are the means to it.

    如霍布斯所述,这些自然法,不如假设的规则发布的绝对命令多,如果你想得到X,你就要去做;,如果你想要和平,这就是方法。

    耶鲁公开课 - 政治哲学导论课程节选

  • Remember, we don't do a one-to-one correlation, because p x and p y are some linear combination of the m plus 1 and m minus 1 orbital.

    记住,我们不需要把它们一一对应,因为px和py轨道是,m等于正负1轨道的线性组合。

    麻省理工公开课 - 化学原理课程节选

  • self y Notice what I also do here, I create self dot y, give it a value, and then, oh cool, I can also set up what's the radius and angle for this point, by just doing a little bit of work.

    我创建了,然后给它赋值,然后,噢太酷了,通过做一点额外的工作,就可以得到点的半径和角度了,好,实际上如果。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • XYZ I might as well do it as x, y, z because we are talking about something that is going in three space.

    我最好设成,因为我们在讨论,三维的事物。

    麻省理工公开课 - 固态化学导论课程节选

  • If I do that, I would like to call the coordinate y, then I will write the same thing.

    如果是那种情形,我会把坐标记为y,然后写出一样的式子

    耶鲁公开课 - 基础物理课程节选

  • I'm going to call it int *y enter or, sorry, semicolon, and then what if I do this?

    我把它叫做int,*y,回车,抱歉,分号,如果我这样处理,会发生什么?

    哈佛公开课 - 计算机科学课程节选

  • What we can actually do is we could solve out for the X and for the Y.

    实际上我们能够解出X和Y的值

    耶鲁公开课 - 博弈论课程节选

  • So let's do c p 1 dot y, c p 2 dot y.

    这不太好因为,两个地方的值都是一样的,对不对?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • And I think in the polar one I said, if, what did I do there, I said, yeah, again if the x and y are greater than the other one, I'm going to return them to it.

    然后我要返回一些值,我认为在极坐标的形式下我说过,如果,我在这里做了什么来着,我说过,对,再说一次,如果x和y坐标。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So I'm going to have an assignment of y, I'm going to have an assignment of iters left, I've got a comment that I had borrowed in order to do some debugging, and then what do I want it to do?

    因此我需要对y进行赋值,需要对iters,left进行赋值,还有一个我用的别人的,用来调试的一些注释,那么接下来我希望程序怎么运行呢?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Once you do that, I think it's fairly clear that it has got a y component that's given by cosine the x component is negative.

    用了这个结论,我想很明显,y 分量由 cos φ 给出,它的 x 分量是负的

    耶鲁公开课 - 基础物理课程节选

  • It adds x to y and stores it into z. But if someone wants to be a even a little more snarky, what does this program do?

    它把x加上y,再把结果存到z中,但是如果有人,想要做的有点不合常理点呢,那这个程序会做什么?

    哈佛公开课 - 计算机科学课程节选

  • Then I do the same thing on line two and I declare something called "y."

    然后我在第二行做了同样的事情,我声明了“y

    哈佛公开课 - 计算机科学课程节选

  • How would I do it?

    怎样解出X和Y的值

    耶鲁公开课 - 博弈论课程节选

  • This now has, gee, a funny thing, x it says IF x is less than y AND x is less than z, then do something.

    代码现在有,啊,一个有趣的东西,代码先是判断x是不是小于y并且,是不是小于z,然后做一些事情。

    麻省理工公开课 - 计算机科学及编程导论课程节选

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