first So what do I do? I find the midpoint by taking last minus first, divide by 2, and add to start.

要怎么做？我把last减去,除以二，加到起点上去。

麻省理工公开课 - 计算机科学及编程导论课程节选

He saw that if you take the atomic mass of chlorine, 2 add it to the atomic mass of iodine, divide by two, you get something that is really close to the atomic mass of bromine.

他看到，如果你将氯的原子质量，加上碘的原子质量，除以，得到的数将与,溴的原子质量很接近。

麻省理工公开课 - 固态化学导论课程节选

So if I start off with a list of length n, how many times can I divide it by 2, until I get to something no more than two left?

我能够除以多少次2呢？,直到我得到的长度不超过2么？,对数次，对吧？就像刚才那位同学说的那样？

麻省理工公开课 - 计算机科学及编程导论课程节选

N Well, here is a list of size N. How many times can you divide a list of size N by 2, right?

这是一个大小为N的列表，将一个大小为,的列表除以2需要几次呢？

哈佛公开课 - 计算机科学课程节选

We can just rewrite that, if I divide through by 2 and rearrange, it's going to tell me that ?1, or if you like, ?1 is equal to 1 plus B S2.

我们这么写,如果我除以2然后整理,可以得出?1等于1+B*S2

耶鲁公开课 - 博弈论课程节选

How many times you can divide N by 2 before you get down to 1?

在得到1之前需要将N除以2做几次呢？

哈佛公开课 - 计算机科学课程节选