-
So I could have written right here immediately CvdT equals Cv dT, and that was the end of my derivation.
于是我在这里就可以直接写,来它等于，完成了整个推导。
-
So if you get these two guys together you get CvdT=-pdV Cv dT is minus p dV.
把它们联系,起来。
-
dU=CvdT So du is still going to be equal to Cv dT, and we're still going to be able to use the first law, all these things don't matter where the path is.
于是，第一定律也依旧成立，这些关系都与路径无关。
-
du, it's an ideal gas. So this is Cv dT and of UB course we can just integrate this straight away.
因此这是CvdT，当然我们可以,直接算出这个积分，那么△
-
dU=CvdT pV=RT So I can write du is Cv dT and pV is equal to RT.
于是。
-
dq=CvdT STUDENT: PROFESSOR BAWENDI: Well, let's see.
学生：在等容过程中：,对理想气体。
-
du It's an ideal gas, and that's equal to w1 prime.
等于CvdT，du，is，Cv，dT。,因为是理想气体，所以等于w1一撇。
-
So it would imply that CvdT du was equal to only the first term Cv dT.
这意味,这du进等于第一项。
-
RT/V this expression becomes Cv dT over T is equal to CvdT/T=-RdV/V minus R dV over V.
这样，or，RT，over，V，bar。，So，now，这个等式就,可以化成。
应用推荐