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He says two of the three opposition parties that signed the Code of Conduct are moles with suspicious ties to the government.
VOA: standard.2009.11.01
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And in particular, I can then ask the following question, which is, what's different between those two pieces of code?
是有个明显的模式的,我特别要问如下的问题，这两块代码的,不同之处在哪儿？
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But if I did have two lines of code or more, I would in fact need to put those back.
但是如果我的确有两行或更多的代码，我其实应该把花括号加上。
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And that does two things: bug one, it helps catch bugs in your code, and secondly it often converts it into a more efficient sequence of instructions before you actually go off and run it. All right?
这有两点好处：,第一是可以帮助你发现程序中的，第二是把你的代码,在运行之前,转换为更有效率的指令的集合，对不对？
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I want the function, which is a little tool, a line of code I can include in my own programs and generally those tools live in sections two or three of the manual.
我想要一个函数，那是一个小工具，在我程序中可以包含的一行代码,通常这些工具在手册的第二节,或第三节。
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And for reference, incidentally, in case you ever forget what the point of some exercise was, I'll almost always comment the code up top with a quick sentence or two that reminds you what this program does.
顺便作为参考，为了避免我们可能忘记一些代码的意思，我通常会用一两个简单的句子,在上面作出注释,那样会提醒我们这个程序是干嘛的。
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Now, we're not quite there because now we have two copies *b=temp of 2 so the last line of code says *b gets temp.
现在，我们还没有达到目的，因为现在我们有两个2的拷贝,最后一行指明。
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> Okay. This code allocates two pointers which can point to integers.
>，好的，这段代码分配两个指针,可以指向整型数。
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So input is an int called F, print out to the screen or your piece of paper the value of C. Odds are you only need two, maybe three lines of code for this, but the goal ultimately will be try it on your own.
所以输入是一个int类型的F，在你的屏幕上,或你们的纸上打印出C的数值,可能你们需要两行或者三行的代码,但是最终的目标需要你自己独自尝试。
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This code does swap the two values, A and B. However, when I run this program, something happens.
这个代码没有交换那两个值，A和B，但是，当我运行这个程序时，有些事情发生了。
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So don't underestimate the value for the next week or two of just inserting printf statements into your code temporarily just to print out what the value of some variable is, or some expression is, so that you can just do a sanity check.
所以不要低估下一两周的重要性,虽然我们只将“printf“语句暂时地植入到,我们的代码中，只是用来打印一些,变量或表达式的值，所以你们提醒一下自己。
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So the very last two lines of code I'm saying this, s2 the original string is s1, the copy of the string is s2, but if I haven't lost you, what are we really going to see when we print this?
最后两行代码是这样的，原字符串是s1，那个字符串的拷贝是，但是如果我没有忘记，当我们打印的时候,我们将看到什么？
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And what we'll be doing is, early next week we'll be distributing code, which we'll ask you to study, about two or three pages of code, and then on the final we'll be asking you questions about the code.
我们现在要做的就是，在下周前半部分我们会发一些代码，给你们去研究，大概有两三页纸，然后在期末的时候,我们会问你一些有关代码的问题。
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Meaning, I'm just going to write a little loop that does that. All right, so let's go back to our code. That's right, let me pull this over a little bit, so I can see it. And what I'd like you to look at, I'm going to highlight it just for a second here, is those two pieces of code.
意思就是我只需,写一个小循环就可以了,让我们回到代码,让我们向下拉一点,我才看得见,我希望你看看这里。
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But what looks like this orange block as of now in Scratch, add orange to your so called inventory, well, it's gonna take at least two lines of code in C to actually create the inventory array with this first line and then put something like the word orange inside of it.
就好比Scratch里面橘色的这一块，把“桔子“加到所谓的“清单“里面去,在C语言中至少需要两行代码来实现,第一行代码创建一个货单数组,第二行就需要把“桔子“放进去。
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As an aside, if you ever just have one line of code that you want to execute, one puzzle piece in Scratch terminology, ; you actually don't need the curly braces; you only need the curly braces if you have two or more lines of code that you want to execute if that condition is true.
此外，如果你只有一行代码,需要执行，在Scratch，术语中叫做,一句代码，你就不需要使用花括号了;,如果那个条件成立，你有两行或更多行的代码时需要执行时,你就需要花括号。
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And in fact, now let me ask those two questions about this piece of code. First question is, for what values of integers-- we're going to assume integers-- but for what values of x does this code terminate? And the second question is, for what values of x does it give me back the right answer?
实际上，让我关于这块代码问两个问题,第一个问题是，对于什么样的整数值，我们会假设是整数,对于x的什么值程序,会最终终止？第二个问题是,对于x的什么值程序,会返回正确答案？
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