But I want to stress again, as long as I do the base case right and my inductive or recursive step reduces it to a smaller version of the same problem, the code will in fact converge and give me out an answer.

就开心的去做吧,但是我想再次强调,只要基础事件处理正确而我的递归,或递推步骤能把它简化为更简单的同类问题,那么这段代码就可以收敛。

麻省理工公开课 - 计算机科学及编程导论课程节选

stdio h This file here is called standard I/O or stdio.h and this is just another text file someone else wrote many years ago and by using that line of code there, I'm telling the computer, give me acces to this code that this other person wrote that's in that file.

在这里的头文件称为标准输入输出文件或,这是由某位前人编写的文本文件,我们只需要刚才所述的一行代码，就能告诉电脑，让我连接到,这个前人在那个文件中写的代码。

哈佛公开课 - 计算机科学课程节选

So this first little piece of code right here says, ok you give me 2 points, I'll create another 1 of these lists and I'll simply take the x, sorry I shouldn't say x, I'm going to assume it's the x, the x-values are the two points, add them together, just right there, the y-values, add them together and return that list.

好，为了来认识到这一点,让我们来看一个简单的小例子，在你们的课堂手册上，你可以看到我写了一个小程序,它假设我得到了，这些点中的一些，我想对它们做一些操作，例如我想把它们加到一起，那么这里的第一小片，代码的意思是，好给我两个点，我会再创建一个数组。

麻省理工公开课 - 计算机科学及编程导论课程节选

And in fact, now let me ask those two questions about this piece of code. First question is, for what values of integers-- we're going to assume integers-- but for what values of x does this code terminate? And the second question is, for what values of x does it give me back the right answer?

实际上，让我关于这块代码问两个问题,第一个问题是，对于什么样的整数值，我们会假设是整数,对于x的什么值程序,会最终终止？第二个问题是,对于x的什么值程序,会返回正确答案？

麻省理工公开课 - 计算机科学及编程导论课程节选