On page 174--Again, check and see if this is the same in your edition.
第174页,又一次,查看,这是不是与你们手中版本的页码一样。
a I'm not, so come down here check palindrome that the two end points a and a are the same and call this again also.
判断两端都是,然后再次调用,注意发生了什么。
So let's charge it up again and see if we can check again.
让我们再次给它充电看看,是否能再次观测到。
I differentiate a second time and check the sign, so the second order condition, I differentiate this expression again with respect to q1.
我们对它进行二次求导然后看符号,这个式子的二阶导数,就是一阶导数再对q1进行求导
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