So the first thing we'll do is, we'll print the element, in this case it will be a list right? Because it's a list with two lists in it.
因此这儿我们要做的第一件事,就是要显示元素,在这儿元素就是数组了对不对?,因为这个数组包含了两个数组。
If it's there, I'm done, if not, I keep walking down, and I only stop when I get to a place where the element I'm looking for is smaller than the value in the list., in which case I know the rest of this is too big and I can stop.
并且保持遍历,我只在当当前位置的数组元素,大于目标数时停止,这意味着剩下的元素都比目标元素大,但是其他的情况,我还是要遍历完整个数组。
Here's the problem. How do I get to the nth- er, the k'th element in the list, in this case?
如何找到第n个元素呢-,在这里,如何找到第k个元素呢?
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