In case 2, we're taking the 3 p out of the neutral atom, whereas in case 3, we're taking it out of the ion.

在第二种情况中，我们要从中性原子中拿走，3，p，电子，而在第三种情况中，我们要从这个离子中拿走它。

麻省理工公开课 - 化学原理课程节选

And in the case of the 3 s orbital, that's going to be equal to 11 . 5 times a nought.

对于３ｓ轨道，它等于１１．５ａ０．

麻省理工公开课 - 化学原理课程节选

In this case, I'm going to get back the answer 3 F-O-O because the user typed in F-O-O, but wait a minute, what's with this?

假若这样，我得到了答案3,因为用户输入了，等一下，用这个干吗？

哈佛公开课 - 计算机科学课程节选

the -- no, I'm not going to cool down, 3 in this case here.

一步，路径。

麻省理工公开课 - 热力学与动力学课程节选

So, in fact, it's not the case that 2 is dominated by 3.

因此说立场2劣于立场3

耶鲁公开课 - 博弈论课程节选

I run out of the house and then usually around 3 o'clock somebody points out, in one case a homeless man, that I have a big glob of shaving cream in my ear or-- because I neglected to actually look in the mirror while I shaved.

然后冲出家门,大概到了下午三点时，会有人跟我说，有一次是一个流浪汉，告诉我，我耳朵上有一团剃须膏-,因为我剃须时忘了,照镜子。

耶鲁公开课 - 心理学导论课程节选

oh, it's kind of hard to compare case 2 and 3 when we can't see it anymore.

噢，我们不太好比较第二和第三选项3,这里看不清了。

麻省理工公开课 - 化学原理课程节选

Let's compare case 2 and 3, since this where some people seem to have gotten confused.

让我们来比较一下第二和第三种情况，因为不少人好像在这里有些困惑。

麻省理工公开课 - 化学原理课程节选

Good, so even if everyone in the number-- everyone in the room didn't choose randomly but they all chose a 100, a very unlikely circumstance, but even if everyone had chosen 100, the highest, the average, sorry, the highest two-thirds of the average could possibly be is 66 2/3, hence 67 would be a pretty good choice in that case.

好的,如果每个人,教室里的每个人不是随机选择数字,而是全选了100,这好像不太可能,但如果每个人真的都选了100,就是最大的书,那平均数,抱歉,平均数的2/3会是66又2/3,此情况下67应该是个不错的选项

耶鲁公开课 - 博弈论课程节选

So we can think of a third case where we have the 3 s orbital, and in the 3 s orbital 0 we see something similar, we start high, we go through zero, where there will now be zero probability density, as we can see in the density plot graph.

第三个例子那就是,3s轨道,在3s轨道里，我们看到类似的现象,开始非常高，然后穿过，这里，概率密度是0，就像你们在概率密度图里看到一样，然后我们到负的。

麻省理工公开课 - 化学原理课程节选

So this code is identical functionally nonswitch c to the last implementation we saw, nonswitch.c, but I'm just ever-more emphatically saying, "In case 1," that is when n equals 1 -- or when case 2 applies -- when n equals 2 or when n equals 3 do what?

所以这些代码到最后的实现上，功能是,完全相同的，但是我想要再次强调一下，“在case，1“，那是当n等于1时1,或者当case，2适用-,当n等于2或者当n等于3，它将做什么？

哈佛公开课 - 计算机科学课程节选