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If its in Cartesian form I'll pass in an x and y and compute what a radius and angle is.
来得到的这个点,我都可以得到这个点的,全部的这种信息。
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If I look at the Cartesian, oh, I did have the Cartesian form, don't mind me while I mutter to myself here quietly.
如果我来看看这个笛卡尔，哦，我还没有笛卡尔形式，当我自言自语的时候,请大家别介意。
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You know when you add 2 polar forms, you add the radii together, you don't add the angles together, you need to do it in Cartesian form.
表示形式的不同理解，返回给你了不同的值，这也就带来了一系列的问题，第二个问题是。
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How do you know whether it's in Cartesian form or in polar form?
这没什么了不起的,但是现在出现问题了？
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If I now say, I'm going to go ahead and change the radius of this, something, my polar form did it right, but what happened to the Cartesian form?
如果我现在说，我要去改变这里的半径,一些这样的操作，我的极坐标形式，进行了正确的改动？
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Oh, but what happened to the Cartesian form.
发生了什么呢？
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It says, if I want to print out something I built in Cartesian form up here, says, again, I'm going to pass it in a pointer to the instance, that self thing, and then I'm going to return a string that I combine together with an open self and close paren, a comma in the middle, and getting the x-value and the y-value and converting them into strings before I put the whole thing together.
这不仅仅是个列表,它是怎么来做的？,流程是：如果我想要返回,一些已经在笛卡尔模式下建好的值，好，再说一遍，我首先要传入一个,指向实例的指针,也就是，然后我会返回一个,由开括号，闭括号,中间的一个逗号,以及提前转换为字符串格式的。
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I should have done this earlier by typing the Cartesian form earlier, so let me go back to where I was, sorry for that, let me go make this a 1 again.
我应该早点通过输入笛卡尔形式,来说明这个的，那么让我回到刚才说到的地方，很抱歉，让我去把，这个a，1再做一遍。
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So for example I defined p, remember back over here, as a Cartesian point, but I can actually ask for its polar form.
我可以要求返回它的极坐标形式，这里对我是可访问的，好，这很棒，请再记另外一个为什么。
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