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So in terms of the first step of skeletal structure, this is actually going to be easier because we don't have a central atom, we just have carbon and nitrogen here.
对于第一步画出骨架，其实比刚才更容易,因为我们没有一个中心原子，我们这里只有碳和氮两个原子。
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However, for carbon and nitrogen we need 8 each.
但是，对于碳和氮，我们都需要八个电子。
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What about between the carbon and nitrogen?
那么碳和氮之间呢？
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So, in order to fill our octet, what we do is put two on the nitrogen and two on the carbon.
因此，为了填满我们的“八隅体“,我们需要将两个放到氮上，将另外两个放到碳上。
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So, shared electrons are the ones that are shared between the carbon and the nitrogen, so we have 6 shared electrons, and we want to take 1/2 of that.
共用电子是那些在碳和氮之间,被它们共用的电子，那么我们有六个共用电子，然后我们要给它乘上二分之一。
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This is very easy molecule because we know exactly where to put them without even having to think, we only have one option, and we'll make a triple bond between the carbon and the nitrogen.
这个分子非常简单,因为我们知道应该把它们放在哪里,甚至不用去想，我们只有一个选择，我们将在碳与氮之间形成一个三键。
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090 We have 1,090 for carbon, 1000 1,000 for sulfur, 1400 and 1,400 for nitrogen.
碳的是，硫的是，而氮的是。
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So we can put actually all 4 of our extra electrons in between the carbon and the nitrogen.
因此我们可以把这剩下的,四个电子都放在碳和氮之间。
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Now we have 6 things around the nitrogen, and we have 8 around the carbon.
现在我们有六个成键电子在氮周围，有八个在碳周围。
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So that takes care of the hydrogen, what about between the carbon and the nitrogen?
因此氢就被排除了，那么碳和氮呢？
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And what you find out if you do these calculations, is that you have a negative 1 for your formal charge on nitrogen, you have a negative 2 for your formal charge on carbon, and you have a positive 2 for your formal charge on sulfur.
而如果你做了这些计算会发现，氮的形式电荷量为负一，碳的形式电荷量为负二，而硫的形式电荷量为正二。
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If we look at our last structure here where we have nitrogen the middle, we can also figure out all those formal charges, and in this case we have plus 1 on the nitrogen, we have minus 2 on the carbon, and then we end up with a 0 on the sulfur there.
如果我们来看看最后一个结构,在中间的原子是氮，我们同样可以计算出所有的形式电荷，而在这种情况下，氮为正一，碳为负二，而最后硫为零。
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