• (Test) The U.N.Secretary-General says he is "optimistic" a climate-change agreement can be reached in Copenhagen that will include specific recommendations on key elements that will take effect immediately.

    VOA: standard.2009.12.09

  • So if we say that l is just talking about our kinetic energy part, our rotational kinetic energy, and we know that electrons have potential energy, then it makes sense that l, in fact, can never go higher than n.

    如果我们说,l仅仅是,描述动能项,我们的旋转动能,我们知道,电子有势能,所以可以理解,l不能比n高。

    麻省理工公开课 - 化学原理课程节选

  • And we can calculate that with the formula that we used, which was just n minus l minus 1 equals the number of nodes.

    这个我们可以用我们以前用过的那个公式来计算,也就是节点数等于n减去l减去1

    麻省理工公开课 - 化学原理课程节选

  • "This is one of the clearest calls repeatedly rendered to the government of Sri Lanka - that the U.N.be allowed to access the area so we can assess independently the situation of civilians,"

    VOA: standard.2009.05.11

  • So if I start off with a list of length n, how many times can I divide it by 2, until I get to something no more than two left?

    我能够除以多少次2呢?,直到我得到的长度不超过2么?,对数次,对吧?就像刚才那位同学说的那样?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • For the U.N.to keep urging that peace be created first before a U.N.peacekeeping force can be sent continues to deny the Somali people badly-needed international forces to assist in the stabilization of that country,".

    VOA: standard.2009.06.26

  • So, the optimal thing to do if you live in a world like this n is to get n as large possible and you can reduce the standard deviation of the portfolio very much and there's no cost in terms of expected return.

    如果现实中也这样简单的话,那么你就尽量增大,这样就能让投资组合的标准差,就会大大降低,从预期收益率的角度来看,这样做的成本是零。

    耶鲁公开课 - 金融市场课程节选

  • N Well, here is a list of size N. How many times can you divide a list of size N by 2, right?

    这是一个大小为N的列表,将一个大小为,的列表除以2需要几次呢?

    哈佛公开课 - 计算机科学课程节选

  • RT So it's delta u plus RT, we can say T1 is the n temperature we've used here, delta n of the gas.

    所以它应该是ΔU加,我们可以在这里用T1,气体的Δ

    麻省理工公开课 - 热力学与动力学课程节选

  • N And we can keep doing"T","A","N", ? and I think you see where it is going.

    然后接着移动字母,T,A,和,我想大家应该知道后面是哪些字母了吧。

    斯坦福公开课 - 7个颠覆你思想的演讲课程节选

  • N You can even abbreviate and put Y or N.

    甚至可以缩写Y或。

    耶鲁公开课 - 新约课程节选

  • And if you put this in the well-ventilated area, if you prepare this outside, the h c n gas will actually be released into the air, so you're safe, you can eat it later.

    而如果你把它们放在通风良好的地方,在室外处理,那么氰化氢气体,将会被释放到空气中,这样你就安全了,过后就可以吃了。

    麻省理工公开课 - 化学原理课程节选

  • If we have n equals 4, what is the highest value of l that we can have?

    如果n等于4,l的最大值是多少?

    麻省理工公开课 - 化学原理课程节选

  • So let's actually just simplify this to the other version of the Rydberg constant, since we can use that here.

    除以n初始的平方,我们把它简化成,另一种形式的Rydberg常数。

    麻省理工公开课 - 化学原理课程节选

  • So we know that we're in the n equals 5 state, so we can find what the binding energy is here.

    我们知道,我们在n等于5的态,我们可以找到结合能是多少。

    麻省理工公开课 - 化学原理课程节选

  • How many times you can divide N by 2 before you get down to 1?

    在得到1之前需要将N除以2做几次呢?

    哈佛公开课 - 计算机科学课程节选

  • If we can sort things, you know, we get this n log n behavior, and we got a n log n behavior overall. But can we actually do better in terms of searching.

    如果我们可以排序,如你所知,我们有n,log,n级别的算法,并且我有一个整体的n,log,n级别的算法,但是我们在搜索方面可以做的更好吗?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • PROFESSOR: Good. So, it's going to be in 3, because that's the shortest energy difference we can have, 3 those 2 are inversely related, so it must be n equals 3.

    教授:好,是3,因为它的能量差最小,红色的是我们能看到的,所以一定是n等于。

    麻省理工公开课 - 化学原理课程节选

  • So, our next level up that we can go is going to be the n equals 2 energy level, but we also have an l and an m value, 0 so our lowest l is going to be a there.

    所以下一个能量,是n等于2的能级,但我们还有l和m的值,所以我们最低的l等于。

    麻省理工公开课 - 化学原理课程节选

  • And the last thing we can think about is how do we name this n h bond, and again, we just name it based on it symmetry.

    最后我们要讨论的是,如何命名这个NH键,同样,我们基于它的对称性命名它。

    麻省理工公开课 - 化学原理课程节选

  • And, in fact, it can't even reach n, because then we would have no potential energy at all in our electron, which is not correct.

    事实上,它连n都达不到,因为如果那样的话,电子就没有势能了,这是不可能的。

    麻省理工公开课 - 化学原理课程节选

  • So for sodium, again, we can write n e 3s1 and then 3 s 1.

    对于钠,再一次,我们可以写Ne然后。

    麻省理工公开课 - 化学原理课程节选

  • So if we go to the ground state, what you see is we're at that lowest energy level, and we only have one possibility for an orbital, because when n equals 1, that's all we can do.

    如果我们在基态上,你可以看到,我们在能量最低的态上,只有一种,可能的轨道,因为n等于1,只有这种可能。

    麻省理工公开课 - 化学原理课程节选

  • So if we say that we have a 2 p orbital here, that means that we can have 2 how many different complete orbitals have a 2 for an n, and a p as its l value? three.

    如果我们说这里有一个“2p“轨道,那就意味着我们有,多少完全不同的轨道对于n有一个,而且对于l值有一个p?3个。

    麻省理工公开课 - 化学原理课程节选

  • If n = 1, x/n can take on only two values: 0 or 1.

    n=1时,x/n的值只可能等于0和1

    耶鲁公开课 - 金融市场课程节选

  • And we can generalize to figure out, based on any principle quantum number n, how many orbitals we have of the same energy, n and what we can say is that for any shell n, there are n squared degenerate orbitals.

    我们可以总结出来,在,主量子数为n的情况下,同一个能量上,有多少个轨道,我们可以说,对任何壳层,有n平方个简并轨道。

    麻省理工公开课 - 化学原理课程节选

  • I could still do the linear case, which is order n or I could say, look, take the list, let's sort it and then search it. But in that case we said well to sort it was going to take n log n time, assuming I can do that.

    我仍然可以做O的线性搜索,或者也可以以这个列表为例,我们先将其进行排序,然后再进行查找,但是在这种情况下,要花费n,log,n的时间去对其进行排序。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • On the other hand, if I want to sort it first, OK, if I want to do sort and search, I want to sort it, it's going to take n log n time to sort it, and having done that, then I can search it in log n time.

    我先排序,好的,如果我想排序再搜索,我要排序,这需要花n,log,n时间排序,然后做完了,我们能花log,n时间搜索,啊,哪一种更好呢?恩,呵呵。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • And we talked about the equation you can use for radial nodes last time, and that's just n minus 1 minus l.

    我们讲过这个用于,计算径向节点的方程,也就是n减去l减去1

    麻省理工公开课 - 化学原理课程节选

  • PROFESSOR: OK. We can have n 4, l 3, and then, sure, we can have m sub l equal negative 2 if l equals 3 What's the second value of l that we can have?

    教授:嗯,我们有n4,l3,然后我们有ml等于-2,如果l等于3,l可以有的第二个值是多少?

    麻省理工公开课 - 化学原理课程节选

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