Ha! But I decided I was feeling good in the warm-up, so I decided,'let's just try for it,' so I did it,".

VOA: standard.2009.08.21

But let's not try and figure out what's going on with this big, big example because we'll get really tired.

但是我们不用去想,这个超大的例子是怎么运行的,因为那太累人了,哦实际上，在我们这么做之前。

麻省理工公开课 - 计算机科学及编程导论课程节选

But let's just try maybe one of the basic questions they could ask, and they can say, all right, de Broglie, so you say that all matter, absolutely all matter has wave-like behavior.

让我们试一试他们,可能问到的一个基础问题，他们会说，好的，德布罗意，你说所有的物质，所有物质绝对会有波的特性。

麻省理工公开课 - 化学原理课程节选

All right. I want to do one more extended example here., because we've got another piece to do, but I want to capture this, because it's important, so let me again try and say it the following way.

很好的问题，谢谢你,我还要带大家去看一个延伸的例子,尽管我们还有别的事情要去做，但是我还是想提提这一点，因为这很重要。

麻省理工公开课 - 计算机科学及编程导论课程节选

So what I wanted to do is loop back, at least with a couple of things that we see recurring and very understandably so, but let's try to clear up a couple of frequently occurring issues.

所以我想要做的是回环，至少用两三个,我们看到的东西返回，并且可以理解地，让我们试着处理几个,频繁发生的事情。

哈佛公开课 - 计算机科学课程节选

I want to try to sum up what we've learned from this discussion, but, first, let's thank John, Alex, and Julia for a really wonderful job.

我想总结一下从这场讨论中我们所学到的，不过首先谢谢约翰，亚历克斯，朱莉娅,谢谢他们的精彩表现。

耶鲁公开课 - 公正课程节选

But let's, at least, try to now focus on the second question.

但请让我们试着集中在第二个问题上。

耶鲁公开课 - 死亡课程节选

Suppose now--harder to imagine, but let's try it-- suppose now that you are an indignant angel and you're playing against, and you know this, you're playing against an evil git.

假设你是一个愤怒天使,我知道这个对你们来说很难,但你现在知道你要和,一个自私鬼博弈

耶鲁公开课 - 博弈论课程节选

But, you know, this undergraduate's very eager to do it, let's let him have a try.

就不值得我再花时间,寻找是否有粒子。

麻省理工公开课 - 化学原理课程节选

It's a little awkward asking questions in here but let's give it a try.

现在问问题不太方便,不过可以试一下。

哈佛公开课 - 计算机科学课程节选

But let's try the big one.

但是让我们试试大数。

麻省理工公开课 - 计算机科学及编程导论课程节选

But let's try and get to grips why.

我们来看看为什么

耶鲁公开课 - 博弈论课程节选

So the best response for Player 1, as a function of what Player 2 chooses, q2, is just equal to the q1 hat in this expression and if I solve that out carefully, I will no doubt make a mistake, but let's try it.

这个就是参与人1的最佳对策,它是参与人2策略q2的一个函数,它和之前的q1帽那个表达式是相等的,虽然我是很仔细地计算的,还是有可能算错的,我来验证一下

耶鲁公开课 - 博弈论课程节选