So what we see is that those six pi electrons are actually going to be de-localized around all six of those atoms.

我们看到,六个π电子会,巡游在所有六个原子周围。

麻省理工公开课 - 化学原理课程节选

That's -Pi times a vector.

就等于用 -π 乘以那个矢量

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So z equals 7 -- this is the cut-off where, in fact, the sigma orbital is going to be higher in energy than the pi 2 p orbitals.

所以z等于7-这是分界点，实际上，sigma轨道能量,要比π2p轨道高。

麻省理工公开课 - 化学原理课程节选

And what we see here is now when we're combining the p, we have our 2 p x and our 2 p y orbitals that are lower in energy, and then our pi anti-bonding orbitals that are higher in energy.

这里我们看到,当我们结合p轨道时，在低能处我们有,2px和2py轨道，π反键轨道在更高的能级处。

麻省理工公开课 - 化学原理课程节选