The way that we can figure this out is using something called bond order, and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.
我们可以用叫做,键序的概念来弄明白它,键序等于1/2乘以成键电子,数目减去反键电子数目。
So we know that it's 1, because we have 1, 2, 3, 4 bonding, minus 2 anti-bonding, and 1/2 of that is a bond order of 1.
我们知道它是,因为我们有1,2,3,4个成键,减去2个反键,它的一半就是键序为1。
So for the bond order we want to take 1/2 of the total number of bonding electrons, so that's going to be 4 minus anti-bonding is 4, so we end up getting a bond order that's equal to 0.
键序等于1/2乘以,总的成键电子数,也就是4,减去反键电子数,也就是4。,所以最后得到键序为0。
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