The B-M-I of someone overweight is between twenty-five and twenty-nine point five.
VOA: special.2009.07.21
I'm going to let t of b be the number of steps it takes to solve the problem of size b.
我会设立一个t作为,计算指数为b的时候解决问题需要的步骤数。
Okay. I'm a producer for a record label called B-Boy Records. One of the original labels
好的,我是B-Boy唱片公司的制作人。B-Boy是最早成立的唱片公司之一。
And,an obese person has a B-M-I above thirty.
VOA: special.2009.07.21
Please choose a rhythm for excerpt one you can choose rhythm A which is or you could choose rhythm B So I'm about to play a piece. It's by Chopin.
请选一个和你听到的相符的节奏,你可以选节奏甲,也可以选节奏乙,我现在要弹一段,肖邦的曲子
Well, A has to get whatever is in B. So now I'm clobbering, as they say, this value here, and at this point in the story, this is not good.
好的,A将获得B中的数据,现在我把这个值删掉,在这个地方,这是不好的。
OK? You can take a quick look at it, a even with the wrong glasses on, it says if a 1 sorry, b is equal to 1, a I'm just going to return a.
你们可以快速的过一遍,它是这么写的:如果,对不起,是b等于,那么就直接返回。
So, let's just arbitrarily put it between these two in this case here, but actually there's no reason we couldn't also put it between oxygen b and c, so I'm going to draw another structure where we have it here.
那么,让我们任意地将它们放在这两个之间,但实际上我们没有理由,不能把它们放在氧原子,B,与,C,之间,因此我将把另外一个结构画在这里。
So prices are determined as follows: prices depend on some parameters I'm just going to call a and b, and let me write the equation and then we'll see what it looks like.
价格由如下因素决定,价格取决于两个参数a和b,我们用方程写一下吧
So we can draw that for 1 s a, we can also draw it for 1 s b, and what I'm saying for the molecular wave function is that we have the interference between the two, and we have a constructive interference, so we end up adding these two wave functions together.
所以我们可以对1sa画出它来,我们也可以对1sb画出它来,对于分子波函数我要说的是,它们两者之间会干涉,这里我们有相长干涉,所以我们得到的是波两个波函数加起来。
It says, in either case in general, t of b-- and this is where I'm going to abuse notation a little bit but I can basically bound it by t, 12 steps plus t of b over 2.
我可以用一个,比12+t的数代表,这里有点不准确的地方,具体的步数依赖于奇数偶数,但是你们可以看到在两个case中。
So I'm done when b minus k equals 1, or k equals b minus 1.
因此b-k=1或k-b=1的时候,我就可以停下来了。
t In the b even case, again I'm going to let t of b be the number of steps I want to go through.
如果b为偶数,那么我还是要用,来代表解决这个问题需要的步骤数。
I see no Mike Smiths because I'm on page 1 A where the A's simply are so I turn to the B's and the C's S and the D's and so forth and finally I get to the S's but in the worst case I've looked through 1,000 or so pages.
第一页没有找到叫Mike,Smith的人1,因为第一页姓名首字母是,于是我又接着找B,C,D……最终到了字母,但最坏的情况是,我翻了几千页才找到。
But I'm not always going to have b as even.
如果b是奇数。
Okay, so I'm going to draw for the case, I'm going to draw the best response of Player I and I'm going to draw the best response for Player II in a minute, for the case B equals 1/4.
好的,我们要画这个案例的图像,我要在图中画出参与人I的最佳对策,一会还要画出参与人II的最佳对策,在这里B等于1/4
And I can solve them, and if I solve them out, I'm going to get something like, let me just be careful, I'm going to get something like: 1 minus B S1* is equal to 1, or S1* equals S2* is equal to 1 over .
我们都会解这个方程,如果解完方程,我们会得到,我得仔细点别算错,我们会得到,1-BS1*=1,或S1*=S2*=1/
Yeah. You're jumping slightly ahead of me, but basically, I'm done when this is equal to 1 right? Because I get down to the base case, so I'm done when b u is over 2 to the k is equal to 1, and you're absolutely right, that's when k is log base 2 of b.
因为这就是最基本的情况了,因此当b/2的k次方等于1的时候就停止了1,你说的太对了,就是k等于b的以2为底的对数的时候,你们都坐的挺靠后的啊,我不知道是不是我讲的不太明白?
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