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The B-M-I of someone overweight is between twenty-five and twenty-nine point five.
VOA: special.2009.07.21
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So I take 2 plus 3 b steps to go through this loop OK. So if b is 300, it takes 902 steps.
好，如果b是300的话就是902步,如果b是3000那就有9002步。
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+3b I've said the product was is 2 plus 3 b.
我们已经说了答案是。
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"That's kind of fun!" "What's your name?" "Broklin,B-R-O-K-L-I-N."
VOA: special.2010.04.30
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What if I collect that blood from patients that are already infected with Hepatitis B, purify the Hepatitis B protein, and inject that back into people?
如果我采集那些乙肝患者的血液,抽提出乙肝病毒的蛋白质,并且将其回注入人体内,将会如何呢
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And,an obese person has a B-M-I above thirty.
VOA: special.2009.07.21
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Please choose a rhythm for excerpt one you can choose rhythm A which is or you could choose rhythm B So I'm about to play a piece. It's by Chopin.
请选一个和你听到的相符的节奏,你可以选节奏甲,也可以选节奏乙,我现在要弹一段,肖邦的曲子
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VOA: special.2010.06.14
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Well, A has to get whatever is in B. So now I'm clobbering, as they say, this value here, and at this point in the story, this is not good.
好的，A将获得B中的数据，现在我把这个值删掉，在这个地方,这是不好的。
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VOA: special.2010.06.14
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If you think of two towns down here, Brive,b-r-i-v-e,famous for its rugby, and Tulle,t-u-l-l-e,which is a capital.
如果你可以想起来这儿的两个城镇,布瑞福,b-r-i-v-e,以英式橄榄球运动而负有盛名,图勒,t-u-l-l-e,是一个省的首府
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"There's no indication that the B-1 breaking off from positive I.D.
VOA: standard.2009.06.08
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Put the same point the other way around: If I can imagine A without B, then A and B have to be logically distinct things.
把这点推而广之,如果我可以想象A在没有B的情况下存在,那么A和B在逻辑上是相互独立的
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"There were some problems with some tactics, techniques and procedures, the way in which close air support was supposed to have been executed in this case, such that, at least with one of the aircraft involved, a B-1 bomber, that plane because of how it takes its bombing routes had to break away from positive I.D.
VOA: standard.2009.06.08
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So we can draw that for 1 s a, we can also draw it for 1 s b, and what I'm saying for the molecular wave function is that we have the interference between the two, and we have a constructive interference, so we end up adding these two wave functions together.
所以我们可以对1sa画出它来，我们也可以对1sb画出它来，对于分子波函数我要说的是,它们两者之间会干涉，这里我们有相长干涉，所以我们得到的是波两个波函数加起来。
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So, suppose I tell you to add two vectors, A and B equal to C, and I say, "What's the result of adding A and B?"
假设我告诉你们将两个矢量相加,A + B = C,我问,"A 加 B 结果是什么"
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If b is odd, what do I do?
跟前面一样？
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It says, if I am in the base case, if b is equal to 1, the answer is just a.
首先解决基本的，如果b等于1的话，那么答案就是a了。
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OK? You can take a quick look at it, a even with the wrong glasses on, it says if a 1 sorry, b is equal to 1, a I'm just going to return a.
你们可以快速的过一遍，它是这么写的：如果,对不起，是b等于，那么就直接返回。
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b OK. In this example I'd use b. All right, as b get-- b is the thing that's changing as I go along here, but it could be things like, how many elements are there in a list if the input is a list, could be how many digits are there in a string if the input's a string, it could be the size of the integer as we go along. All right.?
好，在这个例子里我会用，因为b是一直在变的东西,但是也可能是如下情况：,如果输入是数组的话,变化的就是数组的元素数，如果输入是字符串的话,变化的就是字符串的长度，如果是integer的话,可能就是这个数的大小，对不对？
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I want to then do, I need to find the square root b squared plus h squared, right?
我接下来要求b的平方和h的平方,的和的平方根对不对？
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I'm going to let t of b be the number of steps it takes to solve the problem of size b.
我会设立一个t作为,计算指数为b的时候解决问题需要的步骤数。
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OK. So if I look at this code, first of all I'm calling search, it just has one call, so looks like search is constant, except I don't know what happens inside of b search. So I've got to look at b search.
首先调用一下搜索，就一步调用,看起来搜索是固定的，除非我不知道二分搜索的原理，那我们来看看二分搜索吧,所以让我们看看，第一行打印出来的内容。
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I want to solve a to the b.
下面我就开始讲这种方法了。
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The Hepatitis B vaccine I talked about before produced by recombinant DNA technologies, called Recombivax HB, that's one version of it.
我曾经提到过的通过DNA重组技术,制造的乙型肝炎疫苗,被称作重组乙型肝炎疫苗,那是该疫苗的型号之一
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So I took this to the other side and I divided through by 2b and the b here cancels.
通过移项和通分成2b,就可以消去b了
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I mean if you chose Alpha, you're swinging from A to B-; and from Beta, swinging from B+ to C.
要是你选α,你的分数会在A到B-,选β,分数范围会在B+到C
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It says, in either case in general, t of b-- and this is where I'm going to abuse notation a little bit but I can basically bound it by t, 12 steps plus t of b over 2.
我可以用一个,比12+t的数代表,这里有点不准确的地方,具体的步数依赖于奇数偶数，但是你们可以看到在两个case中。
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So I'm done when b minus k equals 1, or k equals b minus 1.
因此b-k=1或k-b=1的时候，我就可以停下来了。
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t In the b even case, again I'm going to let t of b be the number of steps I want to go through.
如果b为偶数，那么我还是要用,来代表解决这个问题需要的步骤数。
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