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"There were some problems with some tactics, techniques and procedures, the way in which close air support was supposed to have been executed in this case, such that, at least with one of the aircraft involved, a B-1 bomber, that plane because of how it takes its bombing routes had to break away from positive I.D.
VOA: standard.2009.06.08
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B=0 There's going to be some temperature where B is equal to zero. In that case, your gas is going to look awfully like an ideal gas.
在某个温度,这时，实际气体的表现，十分接近理想气体,高于这一温度它是正的。
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Well,you can't tell by thinking about the normal case, because the B-functioning and the P-functioning stop at the same time.
这从通常的例子中是研究不出来的，因为生理功能和人格功能同时结束。
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All right. Let's consider now the second extreme case, or extreme case b, b for our helium atom.
好的让我们现在来考虑,一下第二种极端案例，或者极端案例。
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b The repulsive term goes as some constant lower case b divided by R to the n. N is not the quantum number.
这种斥力很想一个固定的小写字母,被R到n分开的话，N不是量子数。
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In that case, we took the gene for the Hepatitis B protein.
在此种情况下,我们将乙肝病毒的基因同蛋白质外壳分离
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It says, if I am in the base case, if b is equal to 1, the answer is just a.
首先解决基本的，如果b等于1的话，那么答案就是a了。
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So we said B was somewhere between 0 and 1/4, let's draw the case for B equals 1/4.
我们之前也说过B在0到1/4之间,这里我们绘制B=1/4的情况吧
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Now if you're at the temperature which is b higher than the inversion temperature, in that case here, a over RT is small compared to b, and this is going to turn out to be negative.
T>Tinv】,这时a/bR小于,结果是负数，因此如果温度。
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It turns out in the case of Hepatitis B, the way the lifecycle proceeds-- the cells make too much of the protein and not all of it gets assembled into the virus.
结果显示,在乙肝的病案中,病毒生命周期的发展情况,细胞制造了大量的蛋白质,但并不是所有的蛋白质都会组合成病毒
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the abuse is, you know, it's not quite right, it depends upon whether it's all ready, but you can see in either case, after 12 steps, 2 runs through this and down to a problem size b over 2.
在12步以后，两轮过后，这个问题的范围b被缩小了一倍，这为什么很不错呢？,这意味着再来12步。
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In an extreme case b, we had a z effective of 2, so essentially what we had was no shielding at all.
我们有效的z是，所以本质上我们完全没有屏蔽。
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So, let's just arbitrarily put it between these two in this case here, but actually there's no reason we couldn't also put it between oxygen b and c, so I'm going to draw another structure where we have it here.
那么，让我们任意地将它们放在这两个之间，但实际上我们没有理由,不能把它们放在氧原子，B，与，C，之间，因此我将把另外一个结构画在这里。
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In this case we have a double bond between a and b, and in this case we have it between b and c.
在这种情况下，我们在，A，与，B，之间有一个双键，而在这种情况下，双键在，B，与，C，之间。
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And in the even case, I'd square, divide by half, call this again: in the odd case, I go b minus 1 and then multiply by a.
就直接求a的平方的二分之b次方，如果是奇数的话，就去求a的b-1次方乘以a，以此递归下去。
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It says, in either case in general, t of b-- and this is where I'm going to abuse notation a little bit but I can basically bound it by t, 12 steps plus t of b over 2.
我可以用一个,比12+t的数代表,这里有点不准确的地方,具体的步数依赖于奇数偶数，但是你们可以看到在两个case中。
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t In the b even case, again I'm going to let t of b be the number of steps I want to go through.
如果b为偶数，那么我还是要用,来代表解决这个问题需要的步骤数。
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Let's just first fill in this for the b 2 case.
让我们先填完这个B2的情况。
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Yeah. You're jumping slightly ahead of me, but basically, I'm done when this is equal to 1 right? Because I get down to the base case, so I'm done when b u is over 2 to the k is equal to 1, and you're absolutely right, that's when k is log base 2 of b.
因为这就是最基本的情况了，因此当b/2的k次方等于1的时候就停止了1,你说的太对了，就是k等于b的以2为底的对数的时候,你们都坐的挺靠后的啊，我不知道是不是我讲的不太明白？
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On the next step though, this, we get substituted by that. Right, on the next step, I'm back in the even case, it's going to take six more steps, plus t of b minus 1. Oops, sorry about that, over 2.
这一步就是偶数了，这一步会让我们得到，6+t这样的结果，因为b-1现在是偶数了,别忽略这里的细节。
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In the case of the helper cells they stimulate a specific population of B-cells to mature into antibody producing cells, and that antibody is generated against the antigen that stimulated it.
以辅助性T细胞为例,辅助性T细胞刺激特定的B细胞,使这些细胞成长为抗体分泌细胞,抗体分泌细胞产生大量的抗体,以消灭大量增殖的抗原
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sb So in this case we would have 1 s a and 1 s b, and instead we would subtract one from the other, and what we would see is that instead of having additional, more wave function in the middle here, we've actually cancelled out the wave function and we end up with a node.
在这种情况下我们有1sa和，两者相减，我们可以看到不是在，中间有了额外更多的波函数，而是我们消掉了,波函数得到一个节点。
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So what we're going to converge in on to, is the S1*, let's call it in this case, is equal to 1 plus B S2* and that S2* is equal to 1 plus B S1*.
交点的横坐标是S1,暂且这么叫吧,S1*=1+BS2*,而S2*=1+BS1
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Okay, so I'm going to draw for the case, I'm going to draw the best response of Player I and I'm going to draw the best response for Player II in a minute, for the case B equals 1/4.
好的,我们要画这个案例的图像,我要在图中画出参与人I的最佳对策,一会还要画出参与人II的最佳对策,在这里B等于1/4
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