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a You know that what will happen is that heat will flow from a to b from b to c and from a to c. That's common-sense.
你知道会发生的是热量从流向,从流向,以及从流向。
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So let's just compare. Let's compare what C happened in path A to what happened in paths B and C. Yes?
我们比较一下沿,路径A和路径B和,所发生的事有什么不同，什么？
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I see no Mike Smiths because I'm on page 1 A where the A's simply are so I turn to the B's and the C's S and the D's and so forth and finally I get to the S's but in the worst case I've looked through 1,000 or so pages.
第一页没有找到叫Mike，Smith的人1,因为第一页姓名首字母是,于是我又接着找B，C，D……最终到了字母,但最坏的情况是,我翻了几千页才找到。
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They had these little leftovers in there and that's why we end up with these small distances between B and C That's a big step.
他们还有一些剩余,这就是为什么,B和C之间有一小段距离,这是一个大音级
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So, suppose I tell you to add two vectors, A and B equal to C, and I say, "What's the result of adding A and B?"
假设我告诉你们将两个矢量相加,A + B = C,我问,"A 加 B 结果是什么"
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She costs C for sure, that's a wash because B, the way we've worked things out, B was $2, C was $1, So B/2-C is a wash.
她承担C的成本,收益是零,因为B,按我们设定的金额,B是2美元,C是1美元,所以B/2-C是零
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If there's no heat flow between the b and c, then I can say all right, a and c were the same temperature.
如果在与之间没有热量流动，那么我就可以说，好吧与处于相同的温度。
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Here's heat exchanged in pathway A and in pathway B heat is zero, and in pathway C, Cv here is qC it's Cv T1 minus T2.
这是qA，这是路径A上的热量交换,路径B中的热量交换是零，而在路径C中，这是qC，它是。
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Here's a - c over 2b and here's a - c over b.
这里是/2b,这里是/b
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I personally don't like swings that much and it's the B-/B+ range, so I'd much rather prefer that to a swing from A to C, and that's my reason.
我不喜欢成绩波动很大的,比如B-/B+这个范围,所以我还是喜欢像A到C这样小点的,这就是我的原因
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A to B is one distance, which is a large one, and B to C is only half that distance, and that's because of the way the Greeks laid this thing out with their two to one ratios, three to two ratios and so on.
到B是一个距离,比较大,而B到C只有半个距离,因为希腊人,用诸如二比一,三比二,之类的频率比来安排音阶
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