• qB This must be heat q B, right. So again, but now let's also look at our special function.

    这个不是,这应该是热量,对吧?所以又一次,这些是我们熟悉的。

    麻省理工公开课 - 热力学与动力学课程节选

  • Because if b was odd, then b minus one is even which means on the next step, I can cut the problem in half again.

    这意味着我在下一步里解决的问题,规模要小了一半,好,课堂材料的第三题。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • This is related, again, to the frontal lobes and this comes out with the A, not B error.

    这也与额叶有关,并且解释了A非B错误

    耶鲁公开课 - 心理学导论课程节选

  • And again, if we write out what all the terms are, we again have 1 s a squared plus 1 s b squared, but now what we're doing is we're actually subtracting the interference term.

    同样,如果我们把所有的项都写出来,同样我们有1s平方加上1sb平方,先现在我们做的是,我们要减去干涉项。

    麻省理工公开课 - 化学原理课程节选

  • The Mycenaean kings we know, thanks to the Linear B tablets, were referred to, the singular once again is Wanax, and the plural is Wanaktes.

    迈锡尼王正如我们,从B类线形刻板所知的,在古希腊语中被称为瓦纳克斯,复数是Wanaktes

    耶鲁公开课 - 古希腊历史简介课程节选

  • So once again if you both put Alpha then my pair gets a B-.

    如果我们都选α 我对手得B-

    耶鲁公开课 - 博弈论课程节选

  • We'll call this B again.

    这段还是被叫做B阶段。

    耶鲁公开课 - 死亡课程节选

  • Again I should have said first, index 0, the first one. I can similarly go in and say I'd like all the things between index 2 and index 4. And again, remember what a b c that does. Index 2 says start a 0. 1, 2. So a, b, c.

    我还是要说一遍,索引为0的元素,是第一个元素,我可以要求返回索引,2和4之前的所有元素,请记住2,是从0开始的,那么0,1,2对应的是。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • t In the b even case, again I'm going to let t of b be the number of steps I want to go through.

    如果b为偶数,那么我还是要用,来代表解决这个问题需要的步骤数。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • OK. A whole lot of work to basically say again, order b is linear.

    这个方法是随b线性增长的,但是这方法也不错。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • All right, so if we think about b h bond here, again, it's the sigma bond, and we're going to say it's a boron 2 s p 2 hybrid orbital interacting with a hydrogen 1 s orbital.

    这可以告诉我们,为什么它倾向于周围只有6个电子,好了,考虑一下这里的BH键,同样的,它是sigma键,我们说。

    麻省理工公开课 - 化学原理课程节选

  • When we talk about anti-bonding, 1sb essentially we're taking 1 s a and now we're subtracting 1 s b, sigma1s and what we end up with again is sigma 1 s, and the important thing to remember is to write this star here.

    当我们讨论反键时,本质上我们是用1sa减去,最后我们得到,记住这里有个星。

    麻省理工公开课 - 化学原理课程节选

  • And in the even case, I'd square, divide by half, call this again: in the odd case, I go b minus 1 and then multiply by a.

    就直接求a的平方的二分之b次方,如果是奇数的话,就去求a的b-1次方乘以a,以此递归下去。

    麻省理工公开课 - 计算机科学及编程导论课程节选

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