Let's multiply both sides by 2, I'll get 2q1* is equal to a - c over b - q1*.
等式两边同时乘以2,得到,2q1*=/b-q1
And a bit, B-I-T, just a shorthand for binary digit, 2 so a digit of zero over a one, bi means two, you only have two digits.
比特,B-I-T,是binary,digit的简写,从0到1的数字,而bi表示,所以你就只有两个数字。
I claim this quantity is a - c over b such that if Firm 2 produces that much quantity, firm 1 will just produce nothing.
这个量是,/b,如果公司2生产这么多公司1就会停产
So the profit is 2 S1 plus S2 plus B S1 S2 minus S1 squared.
利润是2-S1平方
She costs C for sure, that's a wash because B, the way we've worked things out, B was $2, C was $1, So B/2-C is a wash.
她承担C的成本,收益是零,因为B,按我们设定的金额,B是2美元,C是1美元,所以B/2-C是零
What q2 makes this equal to 0 and Katie's answer is solving out the algebra here is that q2 that solves this must be a - c over b.
2为何值时这个算式等于0呢,凯特回答其实就是算出这个的解,即,q2=/b
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