And if your answer is no, your answer will be no, then you just know you can't use this equation here.
如果不是,那就不能,你就知道,你不能用这个方程了。
It might turn out if I had X-ray vision that what I see is this... Then the answer'd be there's not one train here.
有可能是,我看到的是这样。,答案就不是同一辆火车。
And that idea was, we make a guess in the middle, we test it so this is kind of a guess and check, and if the answer was too big, then we knew that we should be looking over here. If it was too small, we knew we should be looking over here, and then we would repeat.
这些有理数是有序排列的,然后我们的想法是,首先在中间取个数作为猜想数,然后对这个猜想数进行验证,如果由猜想数得到的答案太大,我们知道应该跳过,比猜想数大的那个区间,如果太小的话。
If you know the second derivative of y to be a, then the answer looks like this.
如果你知道y的二阶导数是a,那么这就是答案
.. Then the answer'll be well look ... if what we got is... something like this then of course we do have one single train.
答案就会是,如果我们看到。,这个样子,那么当然是同一辆火车。
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