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The diagonal angle of the painting is very bold and inventive.
VOA: special.2009.07.12
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But because there's this lone pair here, it's pushing down on the other bonds, 5° so we end up with an angle of less than 109 . 5 degrees.
但因为这里有孤对，它会把其它键向下压，所以键角会小于109。
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If I pick an angle of 60 degrees, these are some numbers like half and root 3 over 2.
要是我选择一个 60°的角,上面的系数就会是二分之一和二分之根号三
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Her design is made up of two long black granite pieces that meet at an angle.
VOA: special.2009.05.06
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So what we're predicting is a bond angle of 90 degrees.
垂直的轨道上。
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Some Democrats hope she will win, saying that Angle poses less of a threat to Harry Reid in November.
VOA: standard.2010.06.08
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The ordered swirl of houses and streets from this high angle sprang at her now with the same unexpected, astonishing clarity as the circuit card had.
从这个高的视角，看到的像漩涡一般,排列有序的房屋和街道，就像当初的印刷电路一样，以未曾预料的，令人惊讶的清晰感。
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self y Notice what I also do here, I create self dot y, give it a value, and then, oh cool, I can also set up what's the radius and angle for this point, by just doing a little bit of work.
我创建了，然后给它赋值，然后，噢太酷了，通过做一点额外的工作,就可以得到点的半径和角度了，好，实际上如果。
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And just to give you a sense, if you do a cross-cut of this, you cannot show it from this angle, but it should really be sort of a dumbbell shape with the nodal plane in between the two nuclei.
告诉你们这些就是给你们点概念，假如你们把他横切切开，不能从角度上展示，但它还是会保留几分哑铃的形态,以及在两核之间的节面。
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Ok So, according to this model, 90° what we're seeing is a bond angle of 90 degrees.
我听到不同的答案，OK，，I，hear，a，mix。,根据这个模型，我们看到键角是。
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So if we still have an angle of a 109 . 5 degrees, and again, we still have four unpaired electrons available for bonding, we can make one of those bonds with another s p 3 hybridized carbon, so we're going to make up one pair here.
如果键角仍然是109。,同样，我们还有4个未配对的电子可以用来成键，我们可以用其中的一个,和另外一个sp3杂化碳原子成键，这样我们可以组成一对。
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In that case point p 1 doesn't correspond to this point, it actually corresponds to the point of radius 2 and angle 1, which is about here.
基本上也就是说这是第一个点1,这是第二个点，把它们的值加到一起,然后我就得到了目标点，好，这听起来挺不错的。
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So we do, in fact, have a dependence on what the angle is of the electron as we define it in the orbital.
实际上当我们定义电子在这个轨道,它的波函数的确是和角度有关的。
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And the second point is of radius 3 and angle 1, which is up about there.
半径为2然后角度为1的一个点,也就是差不多在这儿，我认为为了确保我做的是。
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So this squared at the origin is going to be a very high probability, and it decays off as you get farther and farther away from the nucleus or from the center, and that's independent of the angle.
所以这个平方,在原点处非常高，随着离核子的距离,越来越远,它逐渐衰减，并且它和角度是没有关系的。
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It's now got a different radius, same angle, so I just changed the radius of it.
我刚刚改变了它的半径，噢，但是对于笛卡尔形式来说。
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So we can have our two hydrogen atoms come in here, and what we will find is - now that we have all of our orbitals filled up -- so thinking about what this angle is here, would you expect it to be less than or greater than what we saw for ammonia before?
我们在这里有两个氢原子，我们会发现,现在我们所有的轨道都填满了-,考虑一下这里的角度，你们觉得它比在氨中看到的,要大还是要小？
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When we look at this angular part, we see that it's always the square root of 1 over 4 pi, it doesn't matter what the angle is, it's not dependent on the angle.
当我们看这角向部分，可以看到它总是等于１除以４pai开根号，这和是什么角度没有关系，它和角度无关。
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Once I've got that, you notice I can now define a polar point, same way. Notice I've now solved one of my problems, which is, in each one of these cases here, I'm creating both x y and radius angle values inside of there.
你们注意到我现在可以，定义一个极坐标点了，以同样的方式,请注意到现在，我已经解决了我的问题之一了，也就是，在这些例子中的每一个,我在里面都创建了x，y值。
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Frequencies, how many times you go around, f is revolutions per second It's called the angle of velocity.
频率就是一秒转多少圈,因为 f 是每秒转过的圈数,这就是角速度
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This is the easiest question all day, what is the bond angle between all of these?
这个问题很简单，键角是多少？
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For, as Rutherford has shown the assumption of the existence of nuclei, as those in question seems to be necessary in order to account for the results of the experiments on large angle scattering of the alpha rays.
因此卢瑟福,提出了原子核存在的假设，这些关于问题的假设对于,解释阿尔法粒子的,大角度散射是有必要的。
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And if the prism is of sufficient dimension that angle can be magnified.
如果这个棱镜有多个面,可以把角度也放大。
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