• So halfway is the right thing to do, because at each step, I'm guaranteed to throw away at least half the list. Right? And that's nice.

    一半以上的元素,对不对?,这很棒,好,大家猜猜这个算法的增长率是多少?,为什么?太对了。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • We're going to start here and we have this pattern of the major that goes whole, whole, half, whole, whole, whole, half step.

    我们从这里开始,大调模式是这样,它经过,全音,全音,半音,全音,全音,全音,半音级

    耶鲁公开课 - 聆听音乐课程节选

  • With this, if I can assume that accessing the i'th element of a list is constant, then you can't see that the rest of that analysis looks just like the log analysis I did before, and each step, no matter which branch I'm taking, I'm cutting the problem down in half.

    读取数组中的第i个元素,是个常量时间的操作的话,我也就能像以前那样得到,这个算法是对数级复杂度的分析,并且每一步不管我选择哪个区间,我都可以把问题的规模缩小一半。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Then the first time so he came up a major third there and then quickly backed off with just a half step below it, which completely gave it a different feel.

    于是开始的时候,乐曲中出现一个大三和弦,然后快速地降低了半个音,这种变化给人完全不同的感受

    耶鲁公开课 - 聆听音乐课程节选

  • And the last one in the major pattern is a half step from B to C.

    大调模式的最后,是一个从B到C的半音级

    耶鲁公开课 - 聆听音乐课程节选

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