So, the wave function at all of these points in this plane is equal to zero, so therefore, also the wave function squared is going to be equal to zero.
因此这里的,波函数平方也等于零,如果我们说在这整个平面上,任何地方找到一个p电子的概率都是零。
sb So just to say that it's 1 s squared plus 1 s b, all of that together squared.
这就是说它是1sa加上,这整个的平方。
pV=RT p plus a over v bar squared times v bar minus b equals r t. All right if you take a equal to zero, these are the two parameters, a and b. If you take those two equal to zero you have p v is equal to r t.
我们就回到,也就是理想气体,状态方程,下面我们来看看,这个方程。
They tell you precisely what the gases were, what the characteristics of those gases were, and it squared beautifully with all details that we heard about the Delphic Oracle.
他们会准确地告诉你,此为何种气体,以及该气体有何特性,而且它与我们所知的德尔菲神谕的,所有细节都相符合
I can either look at my flow chart, or I can look at the code. If I look at the flow chart, it says, I'm at this point. Look at ANS squared. Is it less than or equal to-- sorry, first of all, 0 ANS squared is 0, is it less than or equal to x, yes.
我可以看流程图也可以看我的代码,如果我看流程图的话,流程图这么说的,在这一点,看看ANS的平方,看是不是小于等于-对不起,首先,ANS的平方是。
So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.
这里不再等于-z的平方,现在我们等于-有效的z的平方,乘以RH除以n的平方。
You need to know how to think about them in the same way we think about s and p orbitals, but for example, you don't yet need to know what all of the names are except for this 3 d z squared here.
你们只要知道,如何像考虑s和p轨道一样,来考虑它们,但你们不需要,知道它们的名字,除了这个3dz2轨道外。
OK. If b is even, then a to the b is the same as a squared all to the b over 2.
就等于a的平方的二分之b次方,好,就是把二挪到外面来了。
And again, if we write out what all the terms are, we again have 1 s a squared plus 1 s b squared, but now what we're doing is we're actually subtracting the interference term.
同样,如果我们把所有的项都写出来,同样我们有1s平方加上1sb平方,先现在我们做的是,我们要减去干涉项。
So if we talk about the probability density and we write that in, it's going to be sigma 1 s star squared, 1sb so now we're talking about 1 s a minus 1 s b, all of that being squared.
如果我们讨论概率密度,而且我们把它写出来,它等于sigma1s星的平方,现在我们说的是1sa减去,这整体再平方。
So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.
我们可以发现有效的z等于n的平凡,乘以电离能除以里德堡常数,这些所有再开方,所以等于n乘以,除以RH整体的平方根。
So, the number of nuclei, 119 if we were to sit and count these as well, is 119. So, we'll multiply that by just pi, r squared, to get that cross-section, and divide all of that by 1 . 39 meters squared.
如果你们数的话,原子核的数是,我们用它乘以πr的平方,得到横截面积,除以1。39平方米。
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