• The prize is worth $1.6 million and Ayala says all the money will go to charity.

    VOA: standard.2010.04.05

  • Again, all the people at 1, all the people at 2, and half the people at 3, so that's 25%.

    就是立场1和立场2的全部票数,加上立场3票数一半,一共是25%

    耶鲁公开课 - 博弈论课程节选

  • The payoff of 2 against 3 is all the people at 1, all the people at 2, so it's 20%.

    如果对手选3而我选2我会得到,立场1和2的全部选票,一共20%

    耶鲁公开课 - 博弈论课程节选

  • The disease - in all its forms - struck 1.5 million Americans last year,killing 560,000.

    VOA: standard.2010.03.25

  • But if the loan to value ratio is greater than one, they won't be able to get all the money back.

    但如果贷款价值比率大于1,他们就不能追回所有的贷款

    耶鲁公开课 - 金融市场课程节选

  • It's just kind of overwhelming." The modest Holcomb, a stocky man who sports a beard, said he is not the one who deserves all the credit in his black USA-1 sled dubbed "Night Train."

    VOA: standard.2010.02.28

  • All right, c p 1 dot y, x I've said assign that to the value 2, 2,0. So now c p 1 has inside of it an x and y value.

    一个特定的版本,我现在命名了一个内置变量,并给它赋值了,我刚刚做的也就是给它。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So, that's the kind of stuff: a little bit of background about myself. So now, 1 let's talk about the perspective of 3.091 All of this will be posted. You can take notes.

    就是这些事情,我自己的,一点背景介绍,现在,我们谈谈这门课程的远景1,这些都会放到网站上去,你们可以记笔记。

    麻省理工公开课 - 固态化学导论课程节选

  • So, let's write this one electron orbital approximation for berylium, that sounds like a pretty complicated question, but hopefully we know that it's not at all, 1s22s2 it's just 1 s 2, and then 2 s 2.

    所以让我们写出,铍的单电子轨道近似,那听起来像是一个更为复杂的问题,但是希望我们知道它一点都不是,它仅仅是。

    麻省理工公开课 - 化学原理课程节选

  • 2 >> All right at this point I see 1, 2 lone souls standing; anyone else?

    好,现在我只看到,两个孤独的人在那站着,还有吗?

    哈佛公开课 - 计算机科学课程节选

  • Harmony is indeed invisible in sense Number 1, you cannot see it with your eyes, but for all that, it can be destroyed.

    和声用无形的第一种解读方式理解,确实是无形的,你看不见它,但是它可以毁灭。

    耶鲁公开课 - 死亡课程节选

  • All right, so gamma is for ideal gas, 1 is bigger than one.

    对理想气体,γ大于。

    麻省理工公开课 - 热力学与动力学课程节选

  • We can delete those strategies and once we delete those strategies, all that's left are choices 1 through 67.

    我们可以剔除那些策略,一旦如此,剩下只有1到67的数

    耶鲁公开课 - 博弈论课程节选

  • How much quantity would Firm 2 have to produce in order to induce Firm 1 not to produce at all?

    公司2的产量达到多少时,公司1会选择停产呢

    耶鲁公开课 - 博弈论课程节选

  • I get all the voters right on top of me at position 1 and she gets everyone else, is that right?

    我得到选择立场1的10%选票,对手得到剩余90%的选票,对吗

    耶鲁公开课 - 博弈论课程节选

  • Don't all come crashing into 1:00 because we don't have the room or the number of exams.

    别再1:00的时候冲进来0,因为我们没有房间,或者考场号。

    麻省理工公开课 - 固态化学导论课程节选

  • 1 So, it's two times 3.12 plus four times 1.31, 6 all divided by six.

    就是2*3。12+4*1。,最后再除以。

    麻省理工公开课 - 固态化学导论课程节选

  • The reason I say that is, by having operator overloading I can use 1 generic interface to all of the objects that I want to use.

    他在大多数情况下都是对的,我要这么说的原因是,通过运算符重载我可以,用一个通用的借口对。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • I'm going to get all the people at position 1 and half the people at position 2 for a total of 15.

    我会获得所有立场1的选票,和立场2一半的选票,就是15%

    耶鲁公开课 - 博弈论课程节选

  • All right. So, when we have, for example, l equal to 1, what kind of orbital is this?

    好,例如,当我们有l等于1时,轨道是哪种类型的?

    麻省理工公开课 - 化学原理课程节选

  • So for example, I can say, what are all the methods associated with the number,or the integer 1?

    所有与数字,或者说整数,相关联的方法是哪些?,你可能已经认出一些来了?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • And here if I choose 2 against 4, I get all the people at 1, all the people at 2, and what?

    如果我选2她选4呢,我会得到立场1和2的选票

    耶鲁公开课 - 博弈论课程节选

  • So for example, if we think about fluorine, 1 s 2 2 s 2 2 p 5 that has an electron configuration of 1 s 2, 2 s 2, 2 p 5, so all we would need to do is add one more electron to get the same configuration as for neon.

    比如,如果我们考虑氟原子的话,它的电子排布是,因此我们所需要做的就是给它加上一个电子,使得它与氖原子的电子排布相同。

    麻省理工公开课 - 化学原理课程节选

  • We put all of this over the Rydberg constant, which is 2 . 1 8 times 10 to the negative 18 joules, and we want to raise this all to the 1/2.

    除以里德堡常数,我们想把这些所有的再开方,所以我们最后。

    麻省理工公开课 - 化学原理课程节选

  • It's going to go all the way down to 1: all the way down to 1.

    这个过程会一直持续下去一直到1,直到只剩下1

    耶鲁公开课 - 博弈论课程节选

  • After all, if we have premises 1, 2 and 3, Only composite things can be destroyed.

    毕竟如果我们有了1,2,3,这些前提,只有合成的东西能毁灭。

    耶鲁公开课 - 死亡课程节选

  • All right we've concluded that 1 is dominated by 2, and 10 is dominated by 9.

    这里总结出立场1劣于立场2,立场10劣于立场9

    耶鲁公开课 - 博弈论课程节选

  • sb So just to say that it's 1 s squared plus 1 s b, all of that together squared.

    这就是说它是1sa加上,这整个的平方。

    麻省理工公开课 - 化学原理课程节选

  • And none of this has an S1 in it, so that all goes away.

    1在这里面就都消掉了

    耶鲁公开课 - 博弈论课程节选

  • All it is sigma 1 s, and then we have two electrons in it, so it's sigma 1 s squared.

    所有的都是sigma1s,上面有两个电子,所以是sigma1s的平方。

    麻省理工公开课 - 化学原理课程节选

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