I'll leave the algebra there, transfer it up here, q1* = q2* = a - c over 3b.

先把算式留在那好了,我在这里再抄一遍吧,q1*=q2*=/3b

耶鲁公开课 - 博弈论课程节选

All right, so that's just solving out the algebra, so we're saying what q solves, a - c over 2b - q2 over 2 = 0.

没错,只需要解出当,/2b-q2/2=0,时q2的值即可

耶鲁公开课 - 博弈论课程节选

What q2 makes this equal to 0 and Katie's answer is solving out the algebra here is that q2 that solves this must be a - c over b.

2为何值时这个算式等于0呢,凯特回答其实就是算出这个的解,即,q2=/b

耶鲁公开课 - 博弈论课程节选