Mosaic is spelled m-o-s-a-i-c.

VOA: special.2009.01.02

Let's multiply both sides by 2, I'll get 2q1* is equal to a - c over b - q1*.

等式两边同时乘以2,得到,2q1*=/b-q1

耶鲁公开课 - 博弈论课程节选

Good, so if I plug q2 = 0 into here, this term disappears and I just get a - c over 2b.

把q2=0代入到算式中,这部分就没有了,只剩/2b

耶鲁公开课 - 博弈论课程节选

How far along do I have to go drop off a - c when I have slope -2b?

斜率-2b的线还要经过哪个横坐标呢

耶鲁公开课 - 博弈论课程节选

I'll just remind us of what these functions are; it's a - c over 2b - q2 over 2 and accordingly for Player 2.

再说一遍,参与人2的方程是,/2b - q2/2

耶鲁公开课 - 博弈论课程节选

I claim this quantity is a - c over b such that if Firm 2 produces that much quantity, firm 1 will just produce nothing.

这个量是,/b,如果公司2生产这么多公司1就会停产

耶鲁公开课 - 博弈论课程节选

Now, I claim that that quantity, a - c over 2b actually has another name.

2b这个值是个术语

耶鲁公开课 - 博弈论课程节选

I have 3 q1* is equal to a - c over b; and finally divide by 3 q1* is equal to a - c over 3b.

q1*= /b,最后两边同除以3得,q1*=/3b

耶鲁公开课 - 博弈论课程节选

I got to have a - c over 2b - q2 over 2.

应该是/2b - /2

耶鲁公开课 - 博弈论课程节选

I personally don't like swings that much and it's the B-/B+ range, so I'd much rather prefer that to a swing from A to C, and that's my reason.

我不喜欢成绩波动很大的,比如B-/B+这个范围,所以我还是喜欢像A到C这样小点的,这就是我的原因

耶鲁公开课 - 博弈论课程节选