• In the first match, England's Frank Lampard would have tied the score at 2-all before half-time, but officials did not see his shot bounceacross the goal line and rebound out after hitting under the crossbar.

    VOA: standard.2010.06.29

  • I go up to the green line and go across and this tells me the best response for Firm 2.

    根据这条绿线的对应法则,就可以对应出公司2的最佳对策

    耶鲁公开课 - 博弈论课程节选

  • Now, we're not quite there because now we have two copies *b=temp of 2 so the last line of code says *b gets temp.

    现在,我们还没有达到目的,因为现在我们有两个2的拷贝,最后一行指明。

    哈佛公开课 - 计算机科学课程节选

  • So, let's, for example, look at nitrogen. So n 2, we can do the chart here in green, so it's the green dotted line, and what we see is that we have now defined this energy as where the 2 nitrogen atoms are separated.

    那么,让我们举个例子,看一下氮,那么氮分子,我们可以把它用绿色曲线画在这,这是绿色的虚线,可以看到,我们已经定义为零点能,当两个氮原子分离时。

    麻省理工公开课 - 化学原理课程节选

  • Let's just... We'll get there, just to remind you, the way we read this is you give me a quantity of Firm 2, I find Firm 1's best response by going across to the pink line and dropping down.

    我们当然也能算出来,提醒一下各位,这个图像的个意思是任意给出公司2产量,然后通过这条粉色的线,就可找出与之对应的公司1的最佳对策

    耶鲁公开课 - 博弈论课程节选

  • If you go and work that out, log2 log of two and you have two log two, by math you can show that for the line r series m 2*log2 is equal to two natural log of two, which is 1 1.386 which is greater than one.

    如果你把它计算出来,这二者的对数,你会得到2个,通过数学,你会得到第r列,第m个值,等于,也就是1。386,这大于。

    麻省理工公开课 - 固态化学导论课程节选

  • On line 2, we're gonna induce what's called a loop, so do you wanna go ahead and Philip henceforth you get to stare, stare at the awkwardness.

    第二行,我们将介绍什么叫做循环,你想接着往下读吗,飞利浦正盯着你看,略显尴尬。

    哈佛公开课 - 计算机科学课程节选

  • Go ahead and recite for us line 2 of this program.

    我们看看程序的第二行。

    哈佛公开课 - 计算机科学课程节选

  • But since in drawing Lewis structures actually, in some cases you do, you can draw a dotted line that means a 1 and 1/2 bond, but most in most cases, we just draw out both resonance structures, and the way that we say it's a resonance structure is that we put it in the brackets and we put an arrow between it.

    但是由于在画路易斯结构时,其实,在某些情况下是可以的,你可以画一条虚线来表示一又二分之一键,但是在多数情况下,我们就把两个结构都画出来,而我们说这是一个共振结构的表示的方法是,把它们放在括号里,并在中间放一个双箭头。

    麻省理工公开课 - 化学原理课程节选

  • And there are different choices here 1, 2, 3, and 4 for Player I, and here's the 45o line.

    参与人I有1一直到4的可选策略,这条是45°线

    耶鲁公开课 - 博弈论课程节选

  • So A gets 1, B gets 2, now the swap function itself starts executing line by line; so I declare a chunk of memory called temp.

    所以A等于1,B等于2,现在swap函数自己开始,一行一行地执行,所以我声明了,叫做temp的一块内存。

    哈佛公开课 - 计算机科学课程节选

  • b Star B in the last line of code now means find B, 1 2 3 all right, that's 1, 2, 3.

    在最后一行的*b意思是查找,好的,那是。

    哈佛公开课 - 计算机科学课程节选

  • First there was the observation by Michelson who back in the late 1880s had done very precise interferal metric measurements of the hydrogen lines and had observed that the 656 nanometer line 3 associated with the transition of n equals 3 to n equals 2 was, in fact, a doublet.

    首先是麦克逊,在1880年底的观察,他以公制单位对氢原子的光谱线,作了准确的,无其他因素干扰的,测量,发现当n值由3变为2时,会同时得到波长为656纳米的谱线3,实际上是有两条线。

    麻省理工公开课 - 固态化学导论课程节选

  • So if Player I chooses 4, Player II should choose, I'm sorry, Player II chooses 4, player I should choose 2, and this is a straight line in between.

    如果参与人I选4,参与人II要,说错了,是参与人II选4而I选2,这两点之间是一条直线

    耶鲁公开课 - 博弈论课程节选

  • All right, so one thing that I want to point out, which I said many, many times on Friday, and this is perhaps the last time I'll say it, but one last time is we can think about why we only see a line for the 2 p orbital, versus we don't see separate lines for a 2 p x, a 2 p y, and a 2 p z.

    好的,我还要指出一个问题,这个问题我在上周五已经说了很多很多次了,这可能是我最后一次提到它,但是这最后一次让我们来考虑一下,为什么我们只看到了一条,对应于,2,p,轨道的线,而不是分别对应于,2,p,x,2,p,y,2,p,z,的线?

    麻省理工公开课 - 化学原理课程节选

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