So, a 32 bit of float gives you a bunch of precision.
2比特的浮点型数据精度更大。
Sorry, said that wrong, p1 radius 1 and angle 2, 2 radians is a little bit more than pi half.
而是半径和角度的表示,在这个例子中点,并不对应这个点,它实际上对应的是。
Suppose Firm 1 is pricing at marginal cost and Firm 2 is pricing at something higher, a little bit higher.
假设公司1定价在边际成本,公司2定价稍微高点,高一点点
So right now, it's something like 2% or it's a little bit higher last year, but maybe it'll be 2% going forward.
希勒有可能记错了08年2月份的美国通胀率为4%,略高于去年的水平,但未来应该会维持在2%左右
So it's 2 to the 32, 'cause remember a bit is a 0 or 1.
就是2的32次方,因为1比特只能表示0或。
2,500 A bit, 4 percent for Fed funds and 12,500 for Dow Jones.
基金利率为4%,道琼斯指数在。
now we're not just talking about 1 photon, 1/2 let's say we shoot them all at the same time at our metal, each of them having some energy that's let's say 1/2 the work function. So, just to take a little bit of an informal survey, who thinks here that we will have an electron that is ejected in this case?
我们现在不仅仅讨论一个光子,它们所具有的能量是功函数的,我们在同一时刻把它们打到金属上,我们做一个不太正式的调查,谁认为这种情况下,一个电子会被打出?
Well, here I'm a little bit below 100 and in two, and test one a little bit below 100 as well.
好了我现在在试验2中有一个小于100的数,而实验1也得到了一个小于100的数。
Exactly, so ignoring these first two positions which were a bit weird, choosing 2 always gave me 5% more votes than choosing 1, regardless of what the other person chooses.
完全正确,所以忽略前两个立场,因为前两个立场有点古怪,我们选立场2总比1多获得5%的选票,无论对手如何选择
So, in fact, it is true, it is in fact true, so we can conclude that 2 dominates in fact, we can do a bit better than that we can say strictly dominates 1.
事实的确如此,我们可以得出结论立场2优于立场1,或者更进一步说,立场2严格的优于立场1
And a bit, B-I-T, just a shorthand for binary digit, 2 so a digit of zero over a one, bi means two, you only have two digits.
比特,B-I-T,是binary,digit的简写,从0到1的数字,而bi表示,所以你就只有两个数字。
So, it turns out that in this case, 2 p and any time that we see we're going from a 2 s to 2 p, filling in of electrons, we actually see that little bit of glitch in ionization energy.
在这种情形下的结果就是,任何时候我们从,2,s,到,填充进电子,我们都会看到电离能会稍稍偏离我们的规律。
It says, in either case in general, t of b-- and this is where I'm going to abuse notation a little bit but I can basically bound it by t, 12 steps plus t of b over 2.
我可以用一个,比12+t的数代表,这里有点不准确的地方,具体的步数依赖于奇数偶数,但是你们可以看到在两个case中。
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