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Hong Kong health authorities closed off the hotel on May 1 after a confirmed swine flu case - a Mexican tourist who stayed there.
VOA: standard.2009.05.08
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But if my pair chooses Beta then Alpha yields -1, Beta yields 1: in this case Beta would be better.
但是要是我对手选β我选α得-1,选β得1,此时选β更好
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Well, it looks like it took 1 in this case or it involves-- we can put it another way, merging those two lists involved looking at two numbers, 1, 2, and that's it.
在这种情况下看起来只用了1次-,我们可以从另一个角度看，合并这两个列表涉及到了,2个数字，1，2，就是这样。
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"There were some problems with some tactics, techniques and procedures, the way in which close air support was supposed to have been executed in this case, such that, at least with one of the aircraft involved, a B-1 bomber, that plane because of how it takes its bombing routes had to break away from positive I.D.
VOA: standard.2009.06.08
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So that means it's not possible, if we've made these stipulations in the first place, to have a case where l equals 1.
这说明我们之前的假设,ｌ等于１不可能的。
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Let me generalize this. In this case, my incrementer was just adding 1 to an integer, it's a pretty straightforward thing to do.
当我完成后，我不会再显示任何信息了，好，好，那么你们已经看过两个简单的例子了，让我来讲讲概念，在这个例子中。
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So in this case, my expected payoff is a ? of 1 plus a ? of 4, for a total of again 2.5.
在这种情况下,我预期收益是?乘1加?乘4,总和还是2.5
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Let's look a little bit more closely at Genesis 1 to make this case.
让我们再仔细阅读《创世纪》第一章来了解。
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It's much better--the uncertainty about x/n is much lower for the case n = 100 than it was for the case n = 1, but it's still there.
当n=100时,x/n的不确定性,比n=1时要小得多,但是不确定性仍然是存在的
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In that case point p 1 doesn't correspond to this point, it actually corresponds to the point of radius 2 and angle 1, which is about here.
基本上也就是说这是第一个点1,这是第二个点，把它们的值加到一起,然后我就得到了目标点，好，这听起来挺不错的。
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z So in our first case, our first extreme case, would be that the z effective that is felt by electron number 1, is going to be plus 1.
被1号电子感知到的有效的，是+1所以,我们所能做的是计算出，我们从这个。
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I have sorted with the smaller problem 1 because that smaller problem right now is of size 1 and so it's sort of obviously the case that this cup is now sorted.
对这个较小的问题我已经排好序了,因为在这个小问题中只有1个元素1,那么很明显,这个杯子已经是有序的了。
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In the case of a tower of size 1, basically there are two things to do, right?
如果只有1个圆盘要移动，那么就只要做两件事就可以了对不对？
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So in the first case, I didn't have to do any swaps because 1 was the smallest thing.
所以在第一次遍历中，我没有做,任何的交换因为1就是最小的。
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In the former case if I choose 1 against 4, how many votes do I get?
如果我选立场1对手选立场4,我会获得多少选票
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So 50% in this case, and once again, 2 did better than 1.
综上所述,选择离场2确实比1好
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And the best case scenario here looks like getting a 1 here.
这里最好的情况就是得1了
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So in this case choosing 2 is better than choosing 1.
在这种情况下选择立场2比1好
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Our simplest case that we can look at would be if we had two 1 s orbitals coming together.
最简答的例子是我们可以看一下,如果我们有两个1s轨道,组合起来会怎么样。
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If we look at our last structure here where we have nitrogen the middle, we can also figure out all those formal charges, and in this case we have plus 1 on the nitrogen, we have minus 2 on the carbon, and then we end up with a 0 on the sulfur there.
如果我们来看看最后一个结构,在中间的原子是氮，我们同样可以计算出所有的形式电荷，而在这种情况下，氮为正一，碳为负二，而最后硫为零。
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Often a good thing to start with is to put the lowest ionization energy atom in the middle, and if you don't have charge separation then go with that structure, but if you do find you have a lot of separation, such as the case in negative 2, positive 2, and minus 1, then you want to say wait a second, this is really bad in terms of formal charge, let me go ahead and see what other options I have here.
通常一开始把电离能最低的原子,放在中心位置就很好了，如果你发现电荷没有分开,那么这个结构就没问题了，但是如果你发现有很多分开的电荷，比如这种情况，有负二，正二和负一，那么你会想要说等一下，从形式电荷来看这很不好，让我去看看其它可能的选择。
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H2 So the simplest case we can think of is with h 2 where we have two unpaired electrons, each in a 1 s orbital of a separate h atom.
最容易想到的例子是2,我们有两个未配对电子，每个都在一个分开的1s轨道上。
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So, in the case of boron plus 1, what we are starting with is the ion, so we're starting with a 2 s electron, 2 s 1 and then we're going to 2 s 1 here.
在正一价硼中，我们面对的是这个离子，本来就应该从，2，s，电子开始，然后这里变成。
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So in this case the cross term represents constructive interference between the two 1 s atomic wave functions.
在这种情况下交叉项代表两个,1s原子波函数的相干干涉。
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So we said B was somewhere between 0 and 1/4, let's draw the case for B equals 1/4.
我们之前也说过B在0到1/4之间,这里我们绘制B=1/4的情况吧
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And in the even case, I'd square, divide by half, call this again: in the odd case, I go b minus 1 and then multiply by a.
就直接求a的平方的二分之b次方，如果是奇数的话，就去求a的b-1次方乘以a，以此递归下去。
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When this gets down to t of 1, I'm in the base case.
当问题缩小到t的时候，就是最基本的情况了。
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That's just the those-- let me use my pointer that's just these two lines here. I checked the value, and in one case, I'm changing the last to be mid minus 1, which is the case I'm in here and I just call again. All right?
来看看ppt，这里有两条线,我检查了值，在一种情况下,我把last指向了中点减一,就是这种情况,我们再来调用一下怎么样？
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It says, if I am in the base case, if b is equal to 1, the answer is just a.
首先解决基本的，如果b等于1的话，那么答案就是a了。
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So for example, if you look at the 1 s orbital here, you can see that actually it is lower in the case of the multi-electron atom than it is for the hydrogen atom.
所以举例来说，如果你看到这里的1s轨道,你可以看到实际上,多电子原子情况的。
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