• One over two squared minus one over n squared 3 4 5 where n takes values three, four, five, six.

    除以,2,的平方再减去1除以n的平方,将n赋值为。

    麻省理工公开课 - 固态化学导论课程节选

  • If I'm running a linear algorithm, it'll take one microsecond to complete.

    算法会在1微秒内完成,如果是一个平方级的方法。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • When we have n observations it's just the summation i = 1 to n of 2/n.

    当有n个观察值,这就是在i取1到n时,x减去x均值的平方,除以n的累加

    耶鲁公开课 - 金融市场课程节选

  • If you get one over R squared, it'll be a little steeper.

    如果你用1除以R的平方,它会变得稍微陡峭一些。

    麻省理工公开课 - 固态化学导论课程节选

  • So, we can get from these energy differences to frequency h by frequency is equal to r sub h over Planck's constant 1 times 1 over n final squared minus 1 over n initial squared.

    所以我们通过不同能量,得到不同频率,频率等于R下标,除以普朗克常数乘以1除以n末的平方减去。

    麻省理工公开课 - 化学原理课程节选

  • This S1 squared is going to become a minus 2S1.

    1的平方变成了负2S1

    耶鲁公开课 - 博弈论课程节选

  • And in the even case, I'd square, divide by half, call this again: in the odd case, I go b minus 1 and then multiply by a.

    就直接求a的平方的二分之b次方,如果是奇数的话,就去求a的b-1次方乘以a,以此递归下去。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • If it's not greater than x, take 2. Square it.

    求它的平方,如果1的平方小于等于x的话。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So, for example, 1s1 again we see hydrogen is 1 s 1, helium we say is 1 s 2, or 1 s squared, 1s2 so instead of writing out the 1 s 1 and the 1 s 2, we just combine it 1s22s1 as 1 s squared, lithium is 1 s 2, 2 s 1.

    简化符号所以举例来说,我们又看到氢是,氦是1s2或者1s的平方,所以不是将它写为1s11,而是我们将它合并为1s的平方,锂是。

    麻省理工公开课 - 化学原理课程节选

  • We also know how to figure out the energy of this orbital, and we know how to figure out the energy using this formula here, which was the binding energy, -Rh which is negative r h, we can plug it in because n equals 1, so over 1 squared, and the actual energy is here.

    我们知道如何算出,这个轨道的能级,而且我们知道如何,用这个公式,算出能量,也即是结合能,等于,我们把n等于1代进来,所以除以1的平方,这就是能量。

    麻省理工公开课 - 化学原理课程节选

  • So, the number of nuclei, 119 if we were to sit and count these as well, is 119. So, we'll multiply that by just pi, r squared, to get that cross-section, and divide all of that by 1 . 39 meters squared.

    如果你们数的话,原子核的数是,我们用它乘以πr的平方,得到横截面积,除以1。39平方米。

    麻省理工公开课 - 化学原理课程节选

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