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pV=RT dT here because the pressure is constant, dV=RdT/p so dV is equal to R over p dT.
因为对1摩尔气体有，于是。
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And if we put that in our bond here, we have 1, 2, 3 bonds, plus we have one lone pair left over.
如果我们把它们放到键里，我们有1，2，3个键，还剩下一对孤对在这里。
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In principle, this value, this efficiency, can approach 1 as the low temperature approaches absolute zero.
这个值，效率，当低温热源的温度1,是据对零度时可以达到一。
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And frankly it would be incredibly time-consuming and tedious for me, to count this room full of people old school style-- 1, 2, 3 and so forth.
坦白说，按学校的老办法一个人一个人的数,1个，2个，3个……,对我来说极其费时费力。
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I get all the voters right on top of me at position 1 and she gets everyone else, is that right?
我得到选择立场1的10%选票,对手得到剩余90%的选票,对吗
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Then if I'm looking for the square root of something less than 1, I know it will be in my region, right?
如果我要求平方根的数小于,我就知道我们的答案应该,在0-1这个区间了，对不对？
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If we add one to the return, then you've got a number that's never negative and we can then use geometric returns.
然后加上1,你永远也得不到一个负数,然后我们对这个值求几何平均
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If you look at the electronegativity difference 73 for sodium iodide, it is 1.73.
如果你看到电负性之差,对碘化钠来说，是1。
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So some scholars have speculated that that's the historic reality behind the statement in Exodus 1:18, that a new pharaoh, who knew nothing of Joseph and what he had done for Egypt, began to oppress the Hebrews.
因此一些学者猜测,那是《出埃及记》第1章18节背后的历史事实，一个新的法老，对约瑟夫和他为埃及所做的事情一无所知，开始压迫希伯来人。
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You don't really puzzle your head about questions of interpretation, how we determine the validity of interpretation and so on, until A) meaning becomes terribly important to you, and B) the ascertainment of meaning becomes difficult.
你一般不会在诠释，和如何确定诠释的正确与否，这样的问题上纠结，除非：1，意义对你来说很重要，2，确定意义很困难。
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Now, the Euro is up to a dollar 50 roughly.
目前，欧元对美元大约在1：1。5左右。
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Well, I just think that if he was making his own original idea and it was his idea to start with, then that would be the only situation in which I would see it being appropriate in any way because that way you couldn't make the argument that he was pressured, you know it's three-to-one or whatever the ratio was.
我只是认为，如果这就是他的本意,是他主动要求被杀的，只有在这种情况下,我才认为无论从哪方面来说都是恰当的,因为那样的话，就不能说派克是被迫的，毕竟当时是3对1的局面，派克不占优势。
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All right, so the bonding order, you're correct, should be 2, if we subtract the number of bonding minus anti-bonding electrons and take that in 1/2.
好，你们是对的，键序为，如果我们用成键数,减去反键数除以2。
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And this puzzle piece here colored in blue because it's a Boolean expression is just something that--whose answer is either a yes or no, 0 true or false, one or zero.
这个拼图染成蓝色,因为它是布尔表达式,它的结果只可能是肯定或否定，对或错，1或者。
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Whereas the list assignment you see here did not rebind the object l 1, it changed this. OK?
并没有对包含1的对象做重新绑定,所以这有所改变，对不对？
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So we're going to limit in our discussion in 511-1 for molecular orbital theory to diatomic molecules.
我们在这个课堂上对分子轨道1,理论的讨论仅限于双原子分子。
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So at the very top, I've coded up the same thing as before: "Give me an integer between one and ten," or rather, -- "give me an integer between one and ten" -- a little different this time.
所以在顶部，我像之前那样对同样的东西进行编码：,“给我一个1到10的整数“，或者，“给我一个1到10的整数“,这次有点不同。
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Multiply a by a to the b minus 1.
这很不错对不对？
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This means it is not a strict bond one-to-one.
这意味着不是严格1对1的键。
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But you'll see that very clearly that Steven's right: that choosing 2 will always get me 5% more of the votes than choosing 1 from here on down.
你会发现斯蒂文说的很对,从这里开始,选立场2总会比,选立场1多获得5%选票
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or 1 lone pair, 2 lone pair electrons.
或者说一对孤对电子，两个孤对电子。
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So Christine is correct in saying that once we delete the strategies 1 and 10 once we realize that those positions are not going to be chosen by our sophisticated candidates then we realize that probably choosing 2 isn't a good idea either.
克里斯汀说的很对,一旦我们剔除了策略1和10,一旦我们意识到,不会有人选择这些立场时,我们会发现,选立场2或9可能也不是个好主意了
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If you have a sample with n observations, it's the summation I = 1 to n of xi/n--that's the average.
如果你有n个观测值,对Xi从i=1到n求和再除以n
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Right, 'cause that means either I've been handed zero elements which mean there's really no work to be done or I've been handed one element which is a vacuous truth that it's sorted, right?
因为如果给出0个元素,那意味着不需要做任何事,如果给出1个元素，那显然,它是有序的，对吗？
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And then we'll see if it is. So I think I put in one a two, right? Or one a two?
我认为我们把1a2放进了数组对不对？,那么显示结果应该是1，a，2了？
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All right, so gamma is for ideal gas, 1 is bigger than one.
对理想气体，γ大于。
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V1 This first integral is zero V1 to V1, then I get minus p2 times V2 minus V1 or p2 times V1 minus V2. Again, 0 a positive number.
先保持体积为，对pdV积分1,然后对p2dV从V1到V2积分，第一部分积分为。
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google I'm sure you all use Google, I'm sure it's a verb in your vocabulary, right? Now, Google processes-- ten million?
我相信你们都用,肯定还很熟悉它对不对？,现在Google处理了1千万？
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So, in this program when we call this version of swap 1 and 2 do not end up here, right?
所以，在这个程序中，当我们调用这个swap版本1,和版本2，不是在这里结束，对不？
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OK. We wanted to finish up that section, we're now going to start on a new section, and I want to try and do one and a half things in the remaining time. I'm going to introduce one topic that we're going to deal with fairly quickly, and then we tackle the second topic, it's going to start today, and we're going to carry on.
我们该结束这一段了，现在我们要开始新的课程，我在接下来的时间里要做1。5件事情,我首先会很快的对一个我们,要学习的课题,进行一个介绍，然后再进入第二个话题，今天我们只是开始这个话题，以后还要继续讲。
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