Negative 1 plus 0 should add up to negative 1, if in fact, we're correct for the c n anion.

负一加上零应该等于负一，如果是这样，我们对于氰离子的结果就是正确的。

麻省理工公开课 - 化学原理课程节选

All right, c p 1 dot y, x I've said assign that to the value 2, 2,0. So now c p 1 has inside of it an x and y value.

一个特定的版本，我现在命名了一个内置变量，并给它赋值了,我刚刚做的也就是给它。

麻省理工公开课 - 计算机科学及编程导论课程节选

So those are in fact the patterns of zeroes and ones, the bytes that would have been outputted had I hello c remembered to download the compiler to this computer and run it on that little hello.c file.

这些都是0和1的模式，如果我记得下载编译器到计算机上的话,我们就能运行下这个,然后看看输出的字节。

哈佛公开课 - 计算机科学课程节选

Good, so if I plug q2 = 0 into here, this term disappears and I just get a - c over 2b.

把q2=0代入到算式中,这部分就没有了,只剩/2b

耶鲁公开课 - 博弈论课程节选

You'll put time t=0, x doesn't have this term, doesn't have this term, and it is c.

你令时间t=0,这一项就消失了,这一项也是,只剩下常数c

耶鲁公开课 - 基础物理课程节选

Again I should have said first, index 0, the first one. I can similarly go in and say I'd like all the things between index 2 and index 4. And again, remember what a b c that does. Index 2 says start a 0. 1, 2. So a, b, c.

我还是要说一遍，索引为0的元素，是第一个元素，我可以要求返回索引,2和4之前的所有元素，请记住2,是从0开始的,那么0，1，2对应的是。

麻省理工公开课 - 计算机科学及编程导论课程节选

The bits, the zeros and ones that compose the library are actually - in that file called cs50.c but those bits live or-- even that's a white lie.

这些构成该库的比特--0啊1啊,却是在cs50，c文件里,这些源代码-,可以说是根本不存在。

哈佛公开课 - 计算机科学课程节选

Did the same thing with c p 2, 2 2 0 Again, remind you, c p 2 is a different instance of this data type.

建立了一个x变量，我也把它赋值为，因此cp1内置有了x和y值,然后对cp2做同样的操作。

麻省理工公开课 - 计算机科学及编程导论课程节选

If you want to know what the number c is, you say, let's put time t=0.

比如,如果你想知道系数c代表的是什么,我们令时间t=0

耶鲁公开课 - 基础物理课程节选

What's that telling me is that if Player 2 chooses not to produce then Player 1's best response is a - c over 2b.

参与人2产量为0而参与人1最佳对策是,/2b,这能说明什么

耶鲁公开课 - 博弈论课程节选

In which I said c p 1 dot x equals 1.0.

请注意我上面是怎么做的,创建了cp1和cp2后。

麻省理工公开课 - 计算机科学及编程导论课程节选

But that's not enough because computers at the end 1 of the day only understand 0s and 1s and what you and is clearly not a collection of 0s and 1s.

但是仅仅这样是不够的，计算机,最终只会认识0和,你现在得到的，c的文件显然不是0，1的合集。

哈佛公开课 - 计算机科学课程节选

All right, so that's just solving out the algebra, so we're saying what q solves, a - c over 2b - q2 over 2 = 0.

没错,只需要解出当,/2b-q2/2=0,时q2的值即可

耶鲁公开课 - 博弈论课程节选

What q2 makes this equal to 0 and Katie's answer is solving out the algebra here is that q2 that solves this must be a - c over b.

2为何值时这个算式等于0呢,凯特回答其实就是算出这个的解,即,q2=/b

耶鲁公开课 - 博弈论课程节选

So if I produce one unit it costs me c; if I produce two units it costs me 2c; if I produce 100 units, it'll cost me 100c and if I produce 0.735 units that costs me 0.735c.

生产1单位的产品成本是c,如果生产2单位成本就是2c,如果我生产100单位成本就是100c,如果生产0.735单位就是0.735c

耶鲁公开课 - 博弈论课程节选