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H- *H + e-> H-* And, clearly, we can't do both.
到一个电子生成*,但我们发现我们不能同时做到两个。
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They just gave all the s**t to us
他们把所有的甜食都给我们了，
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*t t of n minus 1 is 3 plus 2 t of n minus 2.
加上。
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You solve for the t* from this one and you put it there.
从这里解出 t*,然后把它代入这个式子
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S**t, I mean. It's pretty bad. I mean.
我的意思是，非常糟糕。
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Now get int *y so now I'll use the board for things I can't really draw very well with the keyboard so what does the memory of my program look like at the moment?
现在，=，int，*y，现在我使用黑板,我用键盘画的不是很好,那么此刻，我程序中的内存看起来像什么？
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For example, if t* is the time you hit the ground, then t* satisfies the equation h - 1/2 g ^2 = 0.
例如,如果在 t* 时刻落地,那 t* 就满足等式 h - 1/2 g ? ^2 = 0
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So this is 3, plus 2 times 3, plus 4 t minus 2.
也就是3+2*3+4t，好。
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If you do that, let's call the particular time t*, then 10t*-10=0, or t* is 1 second.
这样一来,我们把这个时间记为t,所以10t*-10=0,即t*为1秒
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Solve this equation for t*, put it there and that's where you land.
从这个等式里解出 t*,代入那个式子就知道落点了
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If I reduce that it would be 3 plus t of b minus 3, so in general 3*k+t this is 3 k plus t of b minus k. OK.
把b减去一个,在外面加个3就可以了,因此也就是。
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Again, let t* be the time when you hit the ground.
设 t* 为落地的时间
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And conceptually, the idea of cubing a value feels like you could package that up into a little box, a little tool that takes input, a value, and returns output the answer A* so you don't have to constantly do A star, A*A So this program ,at the end of today, is pretty much the same thing.
概念上，算一个值的立方就像是,你可以把一个值打包放在一个小盒子里,一个用来接收输入的工具,一个值，然后返回一个答案,所以你并不需要一直使用，等等。，A，star，，A，，and，so，forth。,这个程序，最后，是一个差不多的东西。
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