You get a set of solutions that are dependent upon -These quantum states fall out of the solution to this equation.

你得到一系列的解,这些解依赖于量子状态,和方程解不相干的解。

麻省理工公开课 - 固态化学导论课程节选

And when you solved the relativistic form of the Schrodinger equation, what you end up with is that you can have two possible values for the magnetic spin quantum number.

当你们解相对论形式的,薛定谔方程，你们最后会得到两个,可能的自旋磁量子数的值。

麻省理工公开课 - 化学原理课程节选

And we also, when we solved or we looked at the solution to that Schrodinger equation, what we saw was that we actually needed three different quantum numbers to fully describe the wave function of a hydrogen atom or to fully describe an orbital.

此外，当我们解波函数,或者考虑薛定谔方程的结果时，我们看到的确３个不同的量子数,完全刻画了氢原子,的波函数或者说轨道。

麻省理工公开课 - 化学原理课程节选

But, as I said before that, we have some more quantum numbers, when you solve the Schrodinger equation for psi, these quantum numbers have to be defined.

但我说了，我们还有，其它的量子数，当你解，psi的薛定谔方程时，必须要，定义这些量子数。

麻省理工公开课 - 化学原理课程节选

psi So we're going to for psi, and before that, we're going to figure out that instead of n just that one quantum number n, we're going to have a few other quantum numbers that fall out of solving the Schrodinger equation for what psi is.

我们要讲到，但在这之前，我们已经知道了,主量子数，现在我们需要知道，其他一些,解psi的薛定谔方程,所需要的量子数。

麻省理工公开课 - 化学原理课程节选

l So, if we're talking about a 4 p orbital, and our equation is n minus 1 minus l, the principle quantum number is 1 4, 1 is 1 -- what is l for a p orbital?

我们方程是n减去1减去，主量子数是，4，1是1，--p轨道的l是多少？,学生：

麻省理工公开课 - 化学原理课程节选

So as I tried to say on the board, we can have n equals 1, 1/2 but since we can't have n equals 1/2, we actually can't have a binding energy that's anywhere in between these levels that are indicated here. And that's a really important point for something that comes out of solving the Schrodinger equation is this quantization of energy levels.

我在这要说的是，我们可以让n等于，但不能让n等于,我们不能得到在这些标出来的,能级之间的结合能，能级的量子化,是从解薛定谔方程中,得到的很重要的一点。

麻省理工公开课 - 化学原理课程节选