But they're great listeners and then they translate that into interactive learning and the organizations tend to be great listening organizations.
他们也善于倾听,然后将其转化为互动式学习,那么整个团队也会变得善于倾听。
and you can go through that by yourself. It doesn't really matter that much.
然后你自己过一遍。关系没那么大。
And then we can say, OK, if we have many constituents, what if we have a mixture of stuff?
然后我们可以问,如果我们有很多组分,那么我们把它们混合后会是怎么样?
If the time you are interested in is not zero, you're allowed to cancel it and get the time from here.
如果你们关注的解不是零时刻,那么就可以忽略它,然后从这里解出时间
and something like that and she says something like: "well. I have to make the best of it. won't I?"
以及之类的话,然后她说了:,那么我必须好好利用这个机会,不是吗“
So, shared electrons are the ones that are shared between the carbon and the nitrogen, so we have 6 shared electrons, and we want to take 1/2 of that.
共用电子是那些在碳和氮之间,被它们共用的电子,那么我们有六个共用电子,然后我们要给它乘上二分之一。
If the company gets too leveraged then there's too high a probability that the company will fail and there are costs to bankruptcy.
如果公司的杠杆率太高,那么公司倒闭的可能性会极高,然后会产生破产费用
So let's hear a little bit of this and then we'll stop so they don't sue us for copyright infringement and then we'll go somewhere else and take another chunk.
那么我们听一小段,然后我们就停,免得他们告我们侵权,然后我们又得去找别的段子了
Well, you can't adopt the policy of "I'm going to wait for this pig to dance " and when it does I'm going to reinforce it" because it's going to take you a very long time.
那么,你就不能说,“我要等这头猪跳舞,然后再对它进行强化“,因为这会花掉你很长的时间。
Good, so Steven, anticipating that Patrick is going to think that steven's a sucker but Patrick's going to cheat on him and produce too much, Steven's going to produce a best response to that and he's going to produce this quantity here.
很好,史蒂文预料到到帕特里克认为,自己是个傻瓜然后帕特里克会违约增产,那么史蒂文的最佳对策就是,生产这么数量的产品
So if you would everyone stand up, take on the number 1 and go.
那么,大家都站起来吧,每个人加1,然后继续下去。
Because sometimes the value of a combination is different then the value you would get by just thinking about each one of the parts in isolation and then adding them up.
因为有时一个组合的价值会不同,那么你得到的价值是只单独考虑每一部分,然后把它们相加所得。
And just try to, I try to not be the downer in a situation.
然后就是想办法,我努力让自己不要那么沮丧。
So actually, let's just run it and then we'll talk about what it does.
那么,让我们运行下程序,然后来探讨下程序的功能吧。
so if you go to Yorkshire, then you have,
那么,如果你去约克郡,然后你能看到……
And know intuitively that if they move together, they will behave like an object of mass 5 and the acceleration will again be 2.
凭直觉认为既然它们一起运动,那么它们就相当于一个质量为 5 千克的物体,然后我们可以算出加速度为 2
So, we can put our sulfur in the middle, and then it doesn't really matter how we draw the rest of it, where we put our c l's versus where we put our oxygen.
那么,我们可以把硫放在中间,然后把其它的原子画在哪里就不重要了,把两个氯原子与一个氧原子放在哪里都行。
Suppose the other guy didn't exist, Suppose Pepsi didn't exist, so Coke has the whole market, then we would solve out this problem.
假设对手不存在,假设百事可乐不存在,那么可口可乐占领整个市场,然后我们就可以解决这个问题
Then a brass instrument enters and what is the name of this brass instrument?
然后一个铜管乐器出现了,那么这个铜管乐器是什么
Were going to make it for a mole of gas, T1 so it's R times T1, V and then we'll have dV over V.
假设是有一摩尔气体,那么就是R乘以,然后有dv除以。
So, the first thing we do is put two electrons between h and c, and then two electrons between c and n.
那么,我们先在氢和碳之间放两个电子,然后在碳和氮之间再放两个电子。
Well,what I'd like to do now is move here to a couple of additional pieces, and we're going to use an example of pop music now with a three-chord chord progression.
那么,我们现在要做的是再看其他一些音乐,然后我们会用流行音乐的例子来看看三和弦进行。
If the probability is 1 in 1,000 that a house burns down and there are 1,000 houses, then the probability that they all burn down is 1/1000 to the 1000th power, which is virtually zero.
如果一栋房子着火的概率是千分之一,然后假设有1000栋房子,那么这一千栋房子全都着火被烧掉的概率,就等于千分之一的一千次方,基本上就是0了
6 Well again, we can go to our ones column, twos, four, eight, 16, 2 damn, 32. So we can go to 32 128 and then we can go to 64, and then 128, 1 2 3 4 5 6 7 8 and this gives me 1, 2, 3, 4, 5, 6, 7, 8.
好吧,再一次回到一位,二位,四位,八位,该死的,32,等等,所以我们可以找到32位2,再64,然后,那么我们就有了。
So, I've got an init in both cases.
好,那么我然后要在这个小小的。
f Well, call toupper pass this lowercase F F to this function called toupper it's going to return capital F and so what do I assign to s2 bracket zero?
调用toupper函数,传递这个小写,然后返回的是大写的,那么我对s2【0】赋值多少?
We then have the 1 s 2 electron, and what is our third electron going to be?
然后是1s电子,那么第三个电子会是什么呢?是的?
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