And what we find out is the wavelength of a Matsuzaka fastball is 1.1 times 10 to the -31 meters.
我们算出松阪快球的波长,是1,1乘以10的负31次方米。
If we think about the size of a typical cell - excuse me, now I'm getting confused about nuclei.
它大约是10的,负十四次方米,如果我们考虑。
This is 10 to the minus 18 joules for this one atom.
对单个原子,就是10的负18次方焦耳。
So if you're not in this 77%, let's quickly go over why, in fact, this is the correct answer, . 9 times 10 to the negative 18 joules.
如果你们不在这77%中,让我们快速的来看一看为什么,这个是正确答案,0,9乘以10的负18次方焦耳。
So now we can just take the negative of that binding energy here, and I've just rounded up here or 1 . 4 times 10 to the negative 19 joules.
等于4是第三激发态,现在我们可以取它结合能的负值,也就是1。4乘以10的负19次方。
So, if we kind of think about the numbers we would need, we would actually need a velocity that approached something that's about 10 to the negative 30 meters per second.
所以如果我们稍微想想,我们需要的数值是多少,我们需要一个,大约为10的负30次方米每秒的速度。
So, we would actually need a really, really, really tiny velocity here to actually overcome the size of the mass, if we're talking about macroscopic particles, to have a wavelength that's going to be on the order.
是10的负34次方焦耳每秒,所以如果我们谈论的是要一个,宏观粒子有相应数量级的波长的话,我们需要一个非常非常非常小的速度来。
So 1.1 times 10 to the -31 meters is not, in fact, a significant number when we're comparing it, for example, to the length of a ball, or the size of the baseball field.
所以1,1乘以10的负31次方米,事实上并不是一个很重要的数字,举例来说,当它与一个球的长度,或者一块棒球场地对比时。
So, if we do this calculation for an electron, saying it moves at 10 to the 5 meters per second, then what we end up with for a wavelength is 7 times 10 to the -9 meters.
如果我们已知电子以,10的5次方每秒的速度运动,那么做一个计算,可以得知它的波长是,7乘以10的负9次方米。
I like the angstrom. It is 10 to the minus 10 meters.
我喜欢单位,埃,它等于10的负10次方米。
If we think of the size of a typical atom, we would say that would be about 10 to the negative 10 meters. So, we can see the diameter of a nucleus is absolutely smaller really concentrating that mass into a very small space.
一个普通细胞的大小,抱歉,我和细胞核搞混了0,如果我们考虑,一个普通原子的大小,这大概是10的负十次方米,所以原子核的直径确实非常小,真的是把质量。
So, let's say we start off at the distance being ten angstroms. We can plug that into this differential equation that we'll have and solve it and what we find out is that r actually goes to zero at a time that's equal to 10 to the negative 10 seconds.
也就大约是这么多,所以我们取初始值10埃,我们把它代入到,这个微分方程解它,可以发现,r在10的,负10次方秒内就衰减到零了。
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