• We've used these effectively to build our electronic systems and our blogs and all of these companies that we're building.

    我们会有效地使用它们,来建立一个电子系统,建立我们的博客和我们建立的,所有的公司。

    斯坦福公开课 - Twitter之父Jack.Dorsey演讲:好奇和灵感的力量课程节选

  • And Pauli says no two electrons in a given system can have the entire set of quantum numbers identical.

    而泡利认为在一个给定的系统内,没有两个电子有完全相同的量子数。

    麻省理工公开课 - 固态化学导论课程节选

  • The reason for that is because all of this is connected, so we're moving electrons everywhere in the system.

    这个现象的原因是因为,它们全部都是连接起来的,所以在这个系统中,电子移动到所有地方。

    麻省理工公开课 - 化学原理课程节选

  • So, we had a pretty good connection to the BBS systems, the bulletin board systems, back then.

    所以我们有一个很好的BBC网络系统,就是电子布告栏系统

    斯坦福公开课 - Twitter之父Jack.Dorsey演讲:好奇和灵感的力量课程节选

  • The radius of the orbit, the energy of the system and the velocity of the electron, I am just going to present you the solutions.

    是轨道的半径,系统的能量,以及电子的速度,我接下来会给你们讲解其方程的解法。

    麻省理工公开课 - 固态化学导论课程节选

  • It tells you that any attempt to try to specify, to localize the position of an electron in such a system is futile.

    这说明你试着任何尝试关于,使一个电子在这样一个系统中,确定其明确的位置是没有意义的。

    麻省理工公开课 - 固态化学导论课程节选

  • And, if you look carefully, it tries to give the sense of a one electron system.

    如果你仔细的观察的话,它试图给人一种单电子系统的感觉。

    麻省理工公开课 - 固态化学导论课程节选

  • And the thing about what Schrodinger did was all he imposed on a system was the electron behaves as a wave and is bound.

    薛定谔所做的,是建立在一个系统之上,电子是像波一样运动的并且是有界限的。

    麻省理工公开课 - 固态化学导论课程节选

  • The total energy of the system, which we are going to get from postulate number four, which says the energy of the electron, which is the energy of the system, is the sum of the kinetic and the potential energy.

    这个系统的总能量,也就是我们将从第四个假设中算出的能量,也就是电子运动产生的能量,也就是整个系统的能量,是动能和位能的总和。

    麻省理工公开课 - 固态化学导论课程节选

  • This one is calculable by the Bohr model because lithium 2plus is a one electron system.

    这个可以通过波尔模型计算而得到,因为锂2+是单电子系统

    麻省理工公开课 - 固态化学导论课程节选

  • How do we put electrons into such a system?

    在这样一个系统里我们怎样放置电子呢?

    麻省理工公开课 - 固态化学导论课程节选

  • So, if we want to go from that stable state to that less stable state, we need to put in a certain amount of energy to our system, that difference between the free electron and the electron bound to the metal.

    所以,如果我们想使电子,从稳态到达不够稳定的状态,我们需要引入一定数量的,能量到系统中,即自由电子和束缚于金属的,电子的能量差。

    麻省理工公开课 - 化学原理课程节选

  • He goes back and redoes the calculation, only in this case he says what I am going to do is I am going to redo the calculation for helium, but I am going to consider not just the mass of the electron but the reduced mass of the system.

    他回去重新做了计算,仅在这种情况下他才会说说我将要,为氦重做计算,但我认为,不只是电子的质量,还有系统质量的减少量。

    麻省理工公开课 - 固态化学导论课程节选

  • How many electrons in the one electron system, right?

    一个单电子系统中有多少个电子,对吗?

    麻省理工公开课 - 固态化学导论课程节选

  • So, helium plus is a one electron system.

    所以氦正离子是一个单电子系统

    麻省理工公开课 - 固态化学导论课程节选

  • So you don't want to put in a negative energy, that's not going to help you out, you need to put in positive energy to get an electron out of the system. So that's why you'll find binding energies are always negative, and ionization energies are always going to be positive, or you could look at the equation and see it from there as well.

    因为这对电离没有帮助,你需要一个正的能量,使得电子脱离这个系统,这就是为什么你会发现,结合能总是负的而电离能总是正的,或者你们看这个方程也可以发现这一点。

    麻省理工公开课 - 化学原理课程节选

  • Remember, because that 1 s orbital is all the way down in terms of if we're thinking about an energy diagram, we're all the way down here, so we have a huge amount of energy we have to put into the system in order to eject an electron.

    还记得吧,因为1,s,轨道在能量示意图里,是在最底部的,我们要一直到最下面,所以我们要向这个系统注入非常大的能量,才能打出一个电子

    麻省理工公开课 - 化学原理课程节选

  • And so the energy is zero because the electron is no longer bound. It is free.

    所以这个系统能量为0,因为,电子不再受束缚了,它自由了。

    麻省理工公开课 - 固态化学导论课程节选

  • In other words, this could be any one electron system.

    另一方面,这可能是单电子系统

    麻省理工公开课 - 固态化学导论课程节选

  • But, I'd give you another one electron system.

    但是我给你的是另一个单电子系统

    麻省理工公开课 - 固态化学导论课程节选

  • That's a one electron system.

    那也是一个单电子系统

    麻省理工公开课 - 固态化学导论课程节选

  • So what we'll end up with is boron plus, 1 s 2 2 s 2 1 s 2, 2 s 2, E and what we say is the delta energy or the change in energy as the same thing as saying the energy of the products minus the energy of our reactant here, that's how much energy we have to put into the system to eject an electron.

    所以结果应该是正一价的硼,电子排布为,我们说,Δ,也就是,E,的变化量,等于生成物的能量,减去反应物的能量,这就是我们从这个系统中,打出一个电子所需要的能量。

    麻省理工公开课 - 化学原理课程节选

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