One thing that makes it pretty clear is that certainly delta S or the sign of it alone is not dictating the outcome here.

这个例子非常清楚的说明,熵增dS或者它的符号,不能单独决定最后的结果。

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I then assign thankful true, if so, but notice this little trick: -- I'm going to keep doing this while I am bang thankful -- bang exclamation point means "not," so this is shorthand, sort of clever elegant notation for "while I'm not thankful, keep doing this."

然后我给thankful赋true值，如果是这样，注意这里有个小技巧：,我将一直这样做，当我用满意时-,感叹号在这里的意思是“非“，这是一个可速记的，有几分机灵优雅的符号,用来说明：“当我不满意，保持这样做“

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