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OK, so what we have to do is get back underneath this reaction, and see what the molar quantities are.
我们应该做的是,再回到这个反应，看看摩尔量是多少。
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Let me show you how you could use this pattern in an example or two or three.
下面我们来看几个例子，看看该如何使用这个句型。
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We started off talking about binary search, and I suggested that this was a log algorithm which it is, which is really kind of nice.
我告诉了你们这是一个对，数级的算法，这是很棒的,我们来一起看看这个算法到底做了什么。
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But it turns out that on Macs and if you have the right software on PCs, you can kind of get a teaser of what this environment tends to look like and be forewarned, what you're about to see is intentionally very underwhelming.
事实上，它是运行在苹果机上的,如果你在电脑上有正确的软件，可以去看看这个环境大致是怎么样的,提前说下，这个程序不会让你印象深刻,我是故意这样做的。
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So, let's consider some people got it wrong, however, and let's see where that wrong answer might have come from, or actually, more importantly, let's see how we can all get to the correct answer.
我们来考虑一下为什么有些人做错了，然而我们来看看,这个错误的答案从何而来，或者事实上更重要的，我们来看看怎样才能都得到正确答案。
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Well, if I want to look at this, I want to have very accurate capabilities in terms of the energy that I use, the light that I use.
嗯，如果我想看看这个，我得有精确的观察能力,根据我用的能量，我接收的光。
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So first, let's start with the one that we already know, and make sure that it still works, starting from here, mainly our isolated system.
首先，我们从我们已知的一个例子入手，看看这个判据是否正确，从绝热系统出发。
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It's a very important point, if you see the very simple math that I'm showing up here.
这一点要特别注意，看看这个简单的数学表达式。
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So let's look at a couple of passages from your sheet, from Heidegger's Being and Time, from his analytic of the hermeneutic circle, and see what Heidegger has to say about this claim.
所以我们看几篇文章，摘自海德格尔的存在与时间，从他对于解释学循环的分析，看看海德格尔对这个观点看法是何。
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So let's just see, look at it a bit.
看仔细了,再好好看看这个博弈
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We have to see how far that goes.
我们可以看看这个能持续多久。
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This is - what this diagram shows you is-- the forces that hold these individual strands of DNA into a double stranded form.
你们可以看看这个图表,演示了连接两条DNA长链为双螺旋,结构的化学力
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Let me give you a few examples of how we can use this pattern in real life.
下面我们来看看如何在生活中使用这个句型。
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You can see how it's laid out. This is the Frost who published that book. This is Frost at thirty-nine, Frost in a suit made by a London tailor in London.
可以看看是怎么排列的，这个是弗罗斯特,当时发表那本书的时候，这个是他39岁，在伦敦穿着伦敦裁缝做的西装。
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And before we do it, I should add one other thing: how, then, do we get these other notes up here, we get these other notes up here?
在此之前,我们先来看看这个,我们如何安排其它这些音符,放在这里吗
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Let's see who can catch this one.
看看谁能接住这个
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Let's look at a few examples of how we can use the "I don't know" pattern.
下面我们来看几个例子，看看该如何使用这个句型。
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There's the Diet Code, this is the weight loss secrets of Leonardo Da Vinci, and you probably didn't know this, but see?
还有减肥密码,这是达芬奇的减肥秘诀,你可能并不知道这个,我们来看看
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That is if I can write code that would solve all instances of smaller size strings, then what I just described isPalindrome will solve the larger size one.
然后我会描述如何处理大字符串,事实上这正是我所做的，我希望你能看看这边的这段代码,就是这个。
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It is just in general that's going to hold true, and that's what I want you to see.
这就是我想讲的，好，让我们来看看最后的这个例子。
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OK, in fact if we look at this, if I say, print of p, it prints it out in that form.
好，实际上如果，我们来看看这个，如果我输入，p的显示。
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It, too, is pretty short, but take a look at what this one does.
它也很短，但先看看,这个是干什么的。
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In addition, if we compare this to the diameter of an atom, which is on the order of somewhere between one and ten angstroms, now we're seeing that, in fact, this wavelength is significantly larger than its environment.
另外，如果我们把它,与原子的直径相比，原子直径近似1到10埃米之间,我们现在来看看，事实上，这个波长比它所处的环境大很多。
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But look at this one.
但是看看这个。
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And I know that sodium chloride forms because, if I look on the webpage at 3.091, you see this down here, this is sodium in kerosene.
我知道氯化钠形式，因为我看过3。091的网站，看看这个，这是钠在煤油中。
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Let's see if we can do that, and it's a little bit of a challenge for the performer.
让我们看看能不能做到这个,对于表演者来说,还真是个挑战呢
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And in fact, if you look down- and I'm just going to highlight this portion, I'm not going to run it- but if you look down here, that's exactly what that does.
实际上，如果你往下看-,我正要强调这一部分，我不会去运行它-,但是如果你看看这儿的话，这个方法确实就是这么做的。
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So, let's look at where this comes from with an energy level diagram here.
让我们从这个能级图,来看看怎么得到这个结果的。
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So let's actually see how we solve this with this function with actual code.
然我们看看怎样用,这个函数和代码解决这个问题。
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pV=RT p plus a over v bar squared times v bar minus b equals r t. All right if you take a equal to zero, these are the two parameters, a and b. If you take those two equal to zero you have p v is equal to r t.
我们就回到,也就是理想气体,状态方程,下面我们来看看,这个方程。
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