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Notice what it says. I'm going to pass in 1 a string, call it s, binds it locally, and it says the following.
然后看接下来的内容,接下来说的是如果这个字符串的长度等于，那么我就成功了。
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and it's going to be followed by a significant bear market
然后接下来会是个很大的熊市，
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And then what I get to do inside the curly braces is literally line by line enumerate the cases that I want to apply to the following code.
然后我们在花括号中要做的是,逐行地列举接下来我想要,应用的代码。
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And then it says, OK, distribute the remaining electrons in pairs so that each atom has eight.
然后它说，接下来将剩下的电子成对排布,使每个原子都有8个电子。
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Which may take up some arbitrary amount of memory. In that case, I'm back to this problem.
然后将接下来的每一个内存块设置为,指向数组对应元素值的指针。
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So from this small, not such a small college you went on to... What was your next destination?
所以说，从这个小学校，也不是太小的学校,你毕业了然后去了。,你接下来做什么了呢？
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What I want you to see is, because I've got two versions of that problem.
我展开一次得到了问题的两个版本，然后接下来是四次。
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All right. Then we're going to set low to-- low and high, and we're going to perform exactly the process I talked about.
不满足条件,我们就可以直接停止运行了，好，接下来我们要定义边界值,然后按照我之前。
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Down here, I've just got two things to merge, and then I've got things of size two to merge and then things of size four to merge. But notice a trade off. I have n operations if you like down there of size one.
但是n的大小是不同的，是吗？在这里我们只要合并两个元素,然后是合并长度为2的列表,接下来是合并长度为4的列表,但是观察一下之间的权衡关系。
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