Whereas the list assignment you see here did not rebind the object l 1, it changed this. OK?

并没有对包含1的对象做重新绑定,所以这有所改变，对不对？

麻省理工公开课 - 计算机科学及编程导论课程节选

I don't have to go read what it printed out in the screen. This has returned a value that I can use. Because I could do a test to say, is this a return value? If it's not, I'll do something else with it. So the binding is still there, it simply doesn't print it out.

我不想读到屏幕中打印出来的这行字,程序返回过一个我能够使用的值,因为我可以做个小测试，来说明这是否是返回的值，如果不是，我可以做一些其它的事,而这个绑定依然在这儿，没有打印任何东西。

麻省理工公开课 - 计算机科学及编程导论课程节选