You've got to juggle the two equations, multiply that by 4, multiply that by 3, add and subtract and so on.
同时处理这两个方程,这个两边乘以4,另一个两边乘以3,将两方程相加或相减求出答案
But then having found one answer, you can add to it anything that gets killed by the act of taking derivatives.
一旦你算出了一个答案,你就可以往式子里加入任何,在求完导后消失的项
Everyone knows from calculus that if you're trying to find a function about which you know only the derivative, you can always add a constant to one person's answer without changing anything.
学过微积分的人都知道,如果你想根据已知的导数,求出其原函数,你总是可以给某人的答案,随便加一个常数,且不影响结果
Well, unfortunately, we know this is not the right answer, because if you take the first derivative, I get 2t.
遗憾的是,我们知道这还不是正确答案,因为如果对它求一阶导数,会得到2t
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