• times 7, plus we have 6 in the sulfur, and oxygen is right above sulfur, so that also has 6.

    二乘上七,加上硫的六个,而氧在硫的正上方,因此也有六个

    麻省理工公开课 - 化学原理课程节选

  • and which of course I understand, like in Massachusetts, six months of the year,

    我很理解这一点,像在马萨诸塞,一年有六个

    加州的天气 - SpeakingMax英语口语达人

  • In this case, 6 valence electrons for each oxygen, so we have 18 total valence electrons.

    在这种情况下,每个氧原子都有六个价电子,因此我们总共十八个价电子。

    麻省理工公开课 - 化学原理课程节选

  • And then there is this group of about half a dozen right down the diagonal middle.

    然后一个包含六个元素的元素组,在周期表的对角线的中部。

    麻省理工公开课 - 固态化学导论课程节选

  • If it was a twenty-year bond, there would be forty coupons, one for each six-month period, and each one would have a date on it.

    假如是20年债券,会40张息票,每六个月一张,并且上面会日期

    耶鲁公开课 - 金融市场课程节选

  • This time you're a doctor in an emergency room and six patients come to you.

    这次你是一名急诊室的医生,天送来了六个病人。

    耶鲁公开课 - 公正课程节选

  • Motive would only go about four, five, six notes.

    动机只会四,五,或六个音符

    耶鲁公开课 - 聆听音乐课程节选

  • So, shared electrons are the ones that are shared between the carbon and the nitrogen, so we have 6 shared electrons, and we want to take 1/2 of that.

    共用电子是那些在碳和氮之间,被它们共用的电子,那么我们有六个共用电子,然后我们要给它乘上二分之一。

    麻省理工公开课 - 化学原理课程节选

  • So in terms of nitrogen that starts off with a valence number of 5, again we have 2 lone pair electrons in the nitrogen, and again, we have 6 electrons that are shared.

    对于氮来说,我们应该从五个价电子开始,同样,氮也两个孤对电子,共用电子的个数也一样,是六个

    麻省理工公开课 - 化学原理课程节选

  • So if we look at sulfur, what we need to do is take the valence electrons in sulfur, and there are 6.

    因此如果我们来看硫原子的话,我们需要做的是,将硫的价电子,有六个

    麻省理工公开课 - 化学原理课程节选

  • And if we talk about chlorine, and both of the chlorines are the same in this case, we start with a valence number of 7 for chlorine, and then we subtract 6, because it had 6 lone pair electrons around each of the chlorine atoms.

    而如果我们讨论氯的话,在这个例子中两个氯的情况都是一样的,从七个价电子开始,然后减去六,因为每个氯原子周围,都有六个孤对电子。

    麻省理工公开课 - 化学原理课程节选

  • And then we end up having 6 shared electrons, 2 from each of the bonds, so we end up with a formal charge on sulfur of plus 1.

    然后我们有六个共用电子,每个键两个,因此最终硫的形式电荷量为正一。

    麻省理工公开课 - 化学原理课程节选

  • This leaves us with 24 minus 18, or 6 bonding electrons left.

    这使得我们二十四减去十八,也就是六个成键电子。

    麻省理工公开课 - 化学原理课程节选

  • If we go to the oxygen atom, now we're talking about starting with 6 in terms of valence electrons again, but instead of 2, you can see we have 6 lone pair electrons around the oxygen minus 1/2 of 2, so we have minus 1 is our formal charge.

    如果我们分析氧原子的话,现在我们讨论的还是,从六个价电子开始,但孤对电子不再是两个了,你会看到氧周围,有六个孤对电子,再减去二的一半,因此我们一个负的形式电荷。

    麻省理工公开课 - 化学原理课程节选

  • So, if we think about what bonds are in this molecule, sp2 we actually have six of these sigma carbon s p 2, carbon s p 2 bonds.

    如果我们考虑这个分子里都什么键,我们有六个sigma碳,碳sp2键。

    麻省理工公开课 - 化学原理课程节选

  • And step four is going to have us figure out how many bonding electrons we have, so we have 16 minus 10, is going to be 6 bonding electrons.

    而第四步需要判断,我们多少个成键电子,那么我们十六减十,也就是六个成键电子。

    麻省理工公开课 - 化学原理课程节选

  • Now we have 6 things around the nitrogen, and we have 8 around the carbon.

    现在我们有六个成键电子在氮周围,八个在碳周围。

    麻省理工公开课 - 化学原理课程节选

  • By looking at the periodic table it's right underneath oxygen, so those both have 6 valence electrons.

    通过查周期表可以看到它就在氧的正下方,因此它们两个都有六个价电子。

    麻省理工公开课 - 化学原理课程节选

  • And if we think about the six hydrogens, now each of those are going to bind by combining one of the carbon hybrid orbitals to a 1 s orbital of hydrogen.

    如果我们考虑有六个氢原子,每个都会合起来,碳杂化轨道成键,每个氢的1s轨道。

    麻省理工公开课 - 化学原理课程节选

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