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So a reversible process leads to requiring certain quantities to be maximized.
因此可逆过程要求,一些物理量要达到最大值。
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And all we mean by constructive interference is that literally those two waves add together, such as the maxima are now twice as high, and the minima are now twice as low.
相干相长，相干相长也就是,说两个波加在一起，所以最大值变成2倍那么高，最低值变成2倍那么低。
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I'm then printing bracket one, bracket two, bracket three, bracket dot, dot, dot up until the total number of arguments, 1 whatever that may be, and it's going to be at least one because the program always has a name.
然后我打印，括号等等等，知道打印完所有的参数，不管那个最大值可能是什么，它将至少为,因为程序总是有一个名字。
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Within a constant shell, it varies from left to right, maximally taking value at the right extreme.
在一个固定的层里，它会从左往右变化，在最右边时达到最大值。
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Then the maximum value I can get is the maximum value of what I had.
我获得的最大值,就是我现有的总值。
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At my maximum, I'll put a hat over it to indicate this is the argmax; at my maximum I'm going to set this thing equal to 0.
给每个最大值都标注上一个帽来,在最大值处导数方程等于0
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A much smaller peak, a much less rapid decline after the peak occurs.
一个较低的峰值,最大值出现后下降速度也较慢
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So, sometimes people get confused when they're solving problems and call the amplitude this distance all the way from the max to the min but it's only half of that because we're only going back to the average level.
解题的时候会弄错，把这个从,最大值到最小值的距离,叫做幅值，但实际上,只有它的一半,只是它和平均值的差距。
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If we have n equals 4, what is the highest value of l that we can have?
如果ｎ等于４,ｌ的最大值是多少？
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Or a subset with the maximum value, there may be more than one, and you're done.
或者是有最大值的子问题集，可能不只一个子问题符合条件，然后就解决问题了。
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And now we want to find the subset of a that has the maximum value, subject to the weight constraint.
会有一个值与其对应,现在我们想要找出满足，重量约束条件的a的最大值子集。
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To find a maximum I want the second derivative to be negative.
最大值处的二阶导数是负数
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So I differentiated this object, this is my first derivative and I set it equal to 0 Now in a second I'm going to work with that, but I want to make sure i'm going to find a maximum and not a minimum, so how do I make sure I'm finding a maximum and not a minimum?
这样我就对它求出导数了,这是一阶导数,令它等于0,一会我们就要计算了,但我先确定一下是最大值还是最小值,我怎么确定是最大值还是最小值呢
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So I've got a function to maximize and a constraint that must be obeyed.
一个需要得到最大值的函数,和一个需要遵守的约束条件。
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8 Here, it gets a maximum value of 48 and 85 calls.
这里它的最大值是8,函数调用了85次。
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I want to maximize that function.
我想得到这个函数的最大值。
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What we're going to do is, we're asking the question, what is the maximum, choosing S1, of this profit.
下面我们要问问我们自己,选S1下利润的最大值是多少呢
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So, that's sort of the mathematically how we get to a, but we can also just look at the graph here, because every time we go one wavelength we can see that we're back in a maximum.
这是就我们得到a的数学,办法，但我们可以直接,从图上看，因为每次我们,经过一个波长，都回到一个最大值。
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where the probability of actually finding an electron there mp is going to be your maximum probability.
电子的概率,达到最大值,我们把它标记成r下标。
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Just write a program to find the max of x and y.
就写个程序找出浮点数x和y中的最大值吧。
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We're going to differentiate with respect to q1, the thing we're trying--our control variable, the thing we're trying to maximize the thing with respect to and set it equal to 0.
对q1求导,q1是控制变量,也就是我们想要求出的最大值,令它等于0
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We're asking the question, taking S2 as given, what S1 maximizes this expression and as the gentleman at the back said, I'm going to differentiate and then I'm going to set the thing equal to 0.
我们来讨论在S2已知的情况下,S1的最大值是多少,就像坐在后排的先生说的那样,我们要去求导然后令导数等于0
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Find the best response function by differentiating this and maximizing the function for every q2, so we could just... Good, so what we're going to do is, all right good, we're going to... We're trying to maximize.
求导得出q2取最大值的情况下,参与人1最佳对策是q2的一个函数,说得很好,接下来,我们要求出最大值
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What I did was I differentiated this fairly simple function with respect to q1 and since I want to find a maximum, what I'm going to do is I'm going to set this thing equal to 0.
只不过是对q1求导了,既然我们要求出最大值,只需要令导数等于0就可以了
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The only place q1 appears here is here, so when I differentiate again I'm going to get -2b and sure enough that's negative, which is what I wanted to know, just to check that when I'm finding this thing, I'm finding a maximum and not a minimum.
只有这一处有q1,因此二阶导数是-2b,它肯定是个负数了,这正是我们想得到的结果,这就验证了我们刚才得出的,是最大值而不是最小值
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