And we can calculate that with the formula that we used, which was just n minus l minus 1 equals the number of nodes.

这个我们可以用我们以前用过的那个公式来计算，也就是节点数等于ｎ减去ｌ减去１

麻省理工公开课 - 化学原理课程节选

So what that means is the compiler is actually going to first "cast" so to speak 13 from whatever it is - to a float -- to a floating point value -- and then perform the division for us.

所以这里的意思是编译器将,做“计算“，譬如13这样一个浮点数,-到另一个浮点数-,然后为我们处理除法。

哈佛公开课 - 计算机科学课程节选

And, in fact, these are the only two types of nodes that we're going to be describing, so we can actually calculate both the total number of notes and the number of each type of node we should expect to see in any type of orbital.

事实上，我们只,描述这两种节点，所以我们可以,计算任何轨道中的,总结点数以及各种节点数。

麻省理工公开课 - 化学原理课程节选

So now we know the Avogadro number and are able to count the quantities accordingly.

所以现在，我们知道阿伏伽德罗数,并且能够以此计算出数值。

麻省理工公开课 - 固态化学导论课程节选

I'm going to let t of b be the number of steps it takes to solve the problem of size b.

我会设立一个t作为,计算指数为b的时候解决问题需要的步骤数。

麻省理工公开课 - 计算机科学及编程导论课程节选