• Now, suppose in fact these weren't x and y glued together, these were radius and angle glued together.

    我实际也说过了,我在这里操作的是,和这两个

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • OK, now that I've got points, I might want to do something with points.

    好,我现在得到了一些,我可能想对这些做一些操作

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • I could do the same thing, I could build polar point.

    很多笛卡尔,我可以做一些同样的操作

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So this first little piece of code right here says, ok you give me 2 points, I'll create another 1 of these lists and I'll simply take the x, sorry I shouldn't say x, I'm going to assume it's the x, the x-values are the two points, add them together, just right there, the y-values, add them together and return that list.

    好,为了来认识到这一,让我们来看一个简单的小例子,在你们的课堂手册上,你可以看到我写了一个小程序,它假设我得到了,这些中的一些,我想对它们做一些操作,例如我想把它们加到一起,那么这里的第一小片,代码的意思是,好给我两个,我会再创建一个数组。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • It says if I want to get the length of a segment, going to pass in that instance, it says from that instance, get the start point, that's the thing I just found.

    它的意思是如果我想要,得到一个线段的长度,首先要把这个实例传进来,然后对于这个实例,从开始,取得x坐标,然后通过同样的操作

    麻省理工公开课 - 计算机科学及编程导论课程节选

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